Answer:
B) Settling a dispute or disagreement
Explanation:
A conflict is a disagreement or argument between opposing parties.
A resolution is a solution to a problem.
Knowing both these definitions, the answer choice that makes the most sense would be B) Settling a dispute or disagreement.
Hope this helps!!
The higher the frequency, the higher or sharper (the musical term if you prefer such things) the pitch is.
Resistor X is the same material and thickness as resistor Y, but it is twice as long. The resistance of resistor X is double that of resistor Y.Option 2 is correct.
<h3>What is resistance?</h3>
Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.
The relation of the resistance with the length and thickness is;
For the given case;
Resistor X has the same thickness and is made of the same material as resistor Y but has twice the length. Resistor X has twice the resistance of resistor Y.
Hence,option 2 is correct.
To learn more about the resistance refer to the link;
brainly.com/question/20708652
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Answer:
240.59 N
Explanation:
We are given that
Mass per unit length=m/l=
Fundamental frequency,f=146.8 Hz
Tension=T=82.4 N
Mass per unit length=
We have to find the tension.
Velocity,v=
New tension,T'=
Hence, the string should have tension 240.59 N so that its fundamental frequency is 146.8 Hz
Let <em>F₁ </em>and <em>F₂</em> denote the two forces, and <em>R</em> the resultant force.
<em>F₁ </em>and <em>F₂</em> point perpendicularly to one another, so their dot product is
<em>F₁ </em>• <em>F₂</em> = 0
<em />
We're given that one of these vectors, say <em>F₁</em>, makes an angle with <em>R</em> of 30°, so that
<em>F₁</em> • <em>R</em> = ||<em>F₁</em>|| ||<em>R</em>|| cos(30°)
But we also have
<em>F₁</em> • <em>R</em> = <em>F₁ </em>• (<em>F₁ </em>+ <em>F₂</em>) = (<em>F₁ </em>• <em>F₁</em>) + (<em>F₁ </em>• <em>F₂</em>) = <em>F₁ </em>• <em>F₁ </em>=<em> </em>||<em>F₁</em>||²
So, knowing that ||<em>R</em>|| = 100 N, we get that
(100 N) ||<em>F₁</em>|| cos(30°) = ||<em>F₁</em>||²
(100 N) cos(30°) = ||<em>F₁</em>||
||<em>F₁</em>|| ≈ 86.6 N
(And the same would be true for <em>F₂</em>.)