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3 years ago

Please help!!! Thank you!!!!!

Physics

1 answer:

MrRa [10]3 years ago

7 0

The amoeba is having a asexual reproduction and the two birds are not. The two birds are having a sexual reproduction.

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A living thing that feeds on Another living thing and may kill it eventually is called

Murljashka [212]

Answer:

(D) parasite........................

3 0

2 years ago

To study the properties of various particles, you can accelerate the particles with electric fields. A positron is a particle wi

maria [59]

Answer:

a) a = 5.03x10¹³ m/s²

b) $V_{f} = 4.4 \cdot 10^{5} m/s$

Explanation:

a) The acceleration of the positron can be found as follows:

$F = q*E$ (1)

Also,

$F = ma$ (2)

By entering equation (1) into (2), we have:

$a = \frac{F}{m} = \frac{qE}{m}$

<u>Where:</u>

F: is the electric force

m: is the particle's mass = 9.1x10⁻³¹ kg

q: is the charge of the positron = 1.6x10⁻¹⁹ C

E: is the electric field = 286 N/C

$a = \frac{qE}{m} = \frac{1.6 \cdot 10^{-19} C*286 N/C}{9.1 \cdot 10^{-31} kg} = 5.03 \cdot 10^{13} m/s^{2}$

b) The positron's speed can be calculated using the following equation:

$V_{f} = V_{0} + at$

<u>Where</u>:

$V_{f}$ : is the final speed =?

$V_{0}$ : is the initial speed =0

t: is the time = 8.70x10⁻⁹ s

$V_{f} = V_{0} + at = 0 + 5.03 \cdot 10^{13} m/s^{2}*8.70 \cdot 10^{-9} s = 4.4 \cdot 10^{5} m/s$

I hope it helps you!

4 0

3 years ago

(m = 4.0 kg) the cockroach rides on the rim (at radius R) of a disk (M = 6.0 kg) that turns about its center like a merry-go-rou

kvasek [131]

Answer:

ω' = 2.5 rad/s

Explanation:

mass of cockroach, m = 4 kg

mass of disk, M = 6 kg

Radius of disc= R

initial angular velocity, ω = 2 rad/s

Let the final angular velocity is ω'

As no external torque is applied, so the angular momentum is constant.

Angular momentum = Moment of inertia x angular velocity

I ω = I' ω'

$\frac{1}{2}\left ( M+m \right )R^{2}\times {2} = \left (\frac{1}{2}MR^{2}+m(0.5R)^{2}) \right )\omega '$

$10R^{2} = 4R^{2}\omega '$

ω' = 2.5 rad/s

5 0

4 years ago

From Doppler shifts of the spectral lines in the light coming from the east and west edges of the Sun, astronomers find that the

Gala2k [10]

Answer:

T= 37 day

Explanation:

To solve this exercise we will use the definition of angular velocity as the angular distance, which for a full period is 2pi between time.

w = T / t

The relationship between angular and linear velocity is

v = w r

w = v / r

We substitute everything in the first equation

v / r = 2π / t

t = 2π r / v

Let's reduce to the SI system

V = 2 km / s (1000m / 1km) = 2 10³ m / s

r= R = 6.96 10⁸ m

Let's calculate

t = 2π 6.96 10⁸/2 10³

t = 3.2 10⁶ s

T = t = 3.2 10⁶ s ( 1h/3600s) (1 day/24 h)

T= 37 day

3 0

3 years ago

A proton enters a uniform magnetic field of strength 1 T at 300 m/s. The magnetic field is oriented perpendicular to the proton’

scZoUnD [109]

A charged particle moving in a magnetic field experiences a force equal to:

$\vec{F}=q\vec{v}\times \vec{B}$

Thus, the magnitude of the force that the proton experiences is given by:

$F=qvBsin\theta$

The magnetic field is perpendicular to the proton's velocity, therefore, we have $\theta=90^\circ$ . Replacing the given values, we obtain:

$F=1.6*10^{-19}C(300\frac{m}{s})(1T)sin(90^\circ)\\F=4.8*10^{-17}N$

3 0

3 years ago