Question

A bungee jumper hangs from a bungee cord with zero velocity. if the bungee cord has a spring constant of 54 n/m and the jumper has a mass of 68 kg, how stretched is the bungee cord past its natural length?

Answer 1

The force that stretches the cord is the weight of the bungee jumper, which is given by:
$F=mg$
where m is the mass of the jumper and g the gravitational acceleration. Substituting, we find
$F=mg=(68 kg)(9.81 m/s^2)=667.1 N$

This force is equal to the elastic force that stretches the cord:
$F=kx$
where k is the spring constant and x is the elongation of the cord. Rearranging the equation, we find x:
$x= \frac{F}{k}= \frac{667.1 N}{54 N/m}=12.4 m$

Answer 2

Answer:

12.3 a p e x.

Explanation: