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Julli [10]
4 years ago
14

Free fall is a situation in which the only force acting upon an object is gravity. Why do all objects in free fall have the same

acceleration?
Physics
2 answers:
Angelina_Jolie [31]4 years ago
5 0

free fall is a special type of motion in which the only force acting upon an object is gravity.  all objects will fall with the same rate of acceleration, regardless of their mass.

stich3 [128]4 years ago
5 0

Answer:

The force of gravity between an object of mass m and Earth M at distance r is as follows (G is gravitational constant):

F = (G) x (m) x (M) / (r^2)

Now, we also know that a force acting on the object is F = (mass) x (acceleration).

Rewrite the first formula as:

F = (m) x (G x M / r^2)

The (G x M / r^2) part is precomputed for the near-surface of Earth and is referred to a gravitational acceleration g:

F = (m) x (g)

As you can see g (or G x M / r^2) does not depend on the mass of the object, only on the mass of Earth but that is the same for all objects in free fall (towards Earth).


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The period T of a simple pendulum is expressed by: √ where ‘l' is the length of the pendulum and ‘g' is the acceleration due to
OlgaM077 [116]

Answer:

T = T

Explanation:

The period of a simple pendulum is given by the formula

                           t = 2\pi \sqrt{\frac{l}{g} }

Where

                         l - length of the pendulum

                         g - acceleration due to gravity

The dimension of the physical quantities are given by,

                                   t  - T

                                   l - L

                                   g - m/s² - LT⁻²

Substituting in the above equation,

                                T = 2π √(L / LT⁻²)

Considering only the dimensional units in the equation

                                 T = √(L / LT⁻²)

                                  T = T

This shows that the formula for a simple pendulum is dimensionally consistent, T = T

3 0
3 years ago
Calculate the intensity of the sound waves from an electric guitar’s amplifier at a
Step2247 [10]

Answer:

a. 0.8 mW/m² b. 1.6 mW/m² c. 6.4 mW/m²

Explanation:

Intensity,I = P/A were P = power and A = area = 4πr² were r = distance from electric guitar = 5.0 m.

a. When P = 0.25 W, I = 0.25 W/4π5² = 0.25 W/100π = 0.00079 W/m² ≅ 0.0008 W/m² =  0.8 mW/m²

b. When P = 0.50 W, I = 0.50 W/4π5² = 0.50 W/100π = 0.00156 W/m² ≅ 0.0016 W/m² =  1.6 mW/m²

c. When P = 2.0 W, I = 2.0 W/4π5² = 2.0 W/100π = 0.00636 W/m² ≅ 0.0064 W/m² =  6.4 mW/m²

8 0
3 years ago
A laser emits light of frequency 4.74 x 1014 hz. what is the wavelength of the light in nm?
Ulleksa [173]
<span>Use this formula:Wavelength=c/v, where c is the speed of light, and v the frequency. 6.33 X 10^-7=3 X 10^8/v v=3 X 10^8/6.33 X 10^-7 v=4.74 X 10^14 Hertz,</span>
5 0
3 years ago
Expectant mothers many times see their unborn child for the first time during an ultrasonic examination. In ultrasonic imaging,
Rzqust [24]

A) A. 380 kHz

To clerly see the image of the fetus, the wavelength of the ultrasound must be 1/4 of the size of the fetus, therefore

\lambda=\frac{1}{4}(1.6 cm)=0.4 cm=0.004 m

The frequency of a wave is given by

f=\frac{v}{\lambda}

where

v is the speed of the wave

\lambda is the wavelength

For the ultrasound wave in this problem, we have

v = 1500 m/s is the wave speed

\lambda=0.004 m is the wavelength

So, the frequency is

f=\frac{1500 m/s}{0.004 m}=3.75\cdot 10^5 Hz=375 kHz \sim 380 kHz

B) B. f(c+v)/c−v

The formula for the Doppler effect is:

f'=\frac{v\pm v_r}{v\pm v_s}f

where

f' is the apparent frequency

v is the speed of the wave

v_r is the velocity of the receiver (positive if the receiver is moving towards the source, negative if it is moving away from the source)

v_s is the speed of the source (positive if the source is moving away from the receiver, negative if it is moving towards the receiver)

f is the original frequency

In this problem, we have two situations:

- at first, the ultrasound waves reach the blood cells (the receiver) which are moving towards the source with speed

v_r = +v (positive)

- then, the reflected waves is "emitted" by the blood cells (the source) which are moving towards the source with speed

v_s = -v

also

v = c = speed of sound in the blood

So the formula becomes

f'=\frac{c + v}{v - v_s}f

C. A. The gel has a density similar to that of skin, so very little of the incident ultrasonic wave is lost by reflection

The reflection coefficient is

R=\frac{(Z_1 -Z_2)^2}{(Z_1+Z_2)^2}

where Z1 and Z2 are the acoustic impedances of the two mediums, and R represents the fraction of the wave that is reflected back. The acoustic impedance Z is directly proportional to the density of the medium, \rho.

In order for the ultrasound to pass through the skin, Z1 and Z2 must be as close as possible: therefore, a gel with density similar to that of skin is applied, in order to make the two acoustic impedances Z1 and Z2 as close as possible, so that R becomes close to zero.

3 0
3 years ago
A woman has a mass of 55 kg on earth. what would be the women's weight on the moon? (The moon’s gravity is 1.6 N).
Alex17521 [72]

Answer:

i dont know the answer sorry have a good day

Explanation:

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8 0
3 years ago
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