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The balanced chemical equation is written as:
<span>CsF(s) + XeF6(s) ------> CsXeF7(s)
We are given the amount of </span>cesium fluoride and <span>xenon hexafluoride used for the reaction. We need to determine first the limiting reactant to proceed with the calculation. From the equation and the amounts, we can say that the limiting reactant would be cesium fluoride. We calculate as follows:
11.0 mol CsF ( 1 mol </span>CsXeF7 / 1 mol CsF ) = 11.0 mol <span>CsXeF7</span>
In chemistry Electronic configuration, also called electronic structure, the arrangement of electrons in energy levels around an atomic nucleus. According to the older shell atomic model, electrons occupy several levels from the first shell nearest the nucleus, K, through the seventh shell, Q, farthest from the nucleus.
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Answer:
to avoid iodine vapor from escaping.
Explanation:
This question is all about an experimental work on the determination of the distribution of iodine between waters and cyclohexane. To understand this question one has to understand the topic "Equilibrium" very well.
One important thing that must be noted in this question is for us to remember that water and cyclohexane are two immiscible liquids. So, when Iodine is added to the two solvents, the iodine dissolves in both water and cyclohexane to certain rate ands then to an equilibrium which is;
Kd = I₂[Cyclohexane]/ I₂[water]. ----------------------------------------[**].
There is a release of I⁻¹ From the added potassium iodide which helps in making sure that the iodine vapor does not escape. Thus, forming a tri-iodide ion.
