<span>Kinetic energy is a body that possesses by
virtue of being in motion. While potential energy possesses a body by virtue of
its position relative to others, stresses within itself, electric charge, and
other factors. As the “car” moves along the track its kinetic energy coverts to
potential energy when it moves up or down one of the hills. With the initial motion
already pushing it when it reaches a slope or dip it uses its own motion to
move along the track. </span>
<span>For
my track I used cardboard and for my “car” I used a spool of thread. The weight
of the cardboard is about .13 kg and the spool is about 0.9</span>
<span>P.s. these were my answers and I got a pretty good grade, for the weight of the track and "car" I did estimate it.</span>
Answer
vvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvvv
Explanation:v
Given : Initial velocity = -1.3 m/s
Final Velocity = -6.5 m/s.
Time = 25 minutes.
To find : Average acceleration.
Solution: We are given units in meter/second (m/s).
So, we need to convert time 25 minutes in seconds.
1 minute = 60 seconds.
25 minutes = 60*25 = 1500 seconds.
Formula for average acceleration is given by,
We are not given intial time, so we can take initial time =0.
Plugging values in the above formula.
=
= -0.003467
or .
Answer:
A) 50 seconds
B) 200 m
Explanation:
They are 500 metres apart.
And one of the bike loves at 6 m/s while the other loves at 4 m/s.
A) Let distance of the 6 m/s bike before they meet be x.
Thus, time = x/6
Since time = distance/speed
For the second bike at 4 m/s, his distance covered before they meet will be 500 - x
Thus, time = (500 - x)/4
Now they will meet each other at the same time. Thus;
x/6 = (500 - x)/4
Cross multiply to get;
4x = 3000 - 6x
6x + 4x = 3000
10x = 3000
x = 3000/10
x = 300 m
Thus, time will be;
t = 300/6
t = 50 seconds
B) Distance covered by the slower bike is (500 - x)
Since from a above, x = 300
Thus; distance = 500 - 300 = 200 m