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lisov135 [29]
3 years ago
6

According to Archimedes’ principle, the mass of a floating object equals themass of the fluid displaced by the object. A swimmer

is floating ina nearby pool; 95% of her body’s volume is in the water while 5% of herbody’s volume is above water. Determine the density of the swimmer’s body.The density of water is Does your answer make sense? Whyor why not?
Physics
1 answer:
ArbitrLikvidat [17]3 years ago
3 0

Answer: 950 Kg/m^3

Explanation: We can deduce from the Archimedes principle that there is a relation between the density and the volumes displaced, as follows:

Density*Volume= Mass

So for equilibrium Density of body= Density of water *Vw/Vb

Being Vw/Vb the relation between  the displaced water and the body volume, and given the water density as 1000 Kg/m^3 we got:

Density(B)= 0.95 * 1000 Kg/m^3.

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The parabolic movement results from the composition of a uniform rectilinear motion (horizontal ) and a uniformly accelerated rectilinear motion of upward or downward motion (vertical ).

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x = x₀+ vx*t   Formula (1)

vx = v₀x

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x: horizontal position in meters (m)

x₀: initial horizontal position in meters (m)

t : time (s)

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t : time in seconds (s)

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We replace data in the  Equation (1)

55 =  120*cosθ

cosθ = 55 / 120

\theta = cos^{-1}(  \frac{55}{120} )

θ = 62.72°

3 0
3 years ago
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