1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Jlenok [28]
3 years ago
6

If the force magnitude increases when the objects are released and free to move, are the objects of the same charge or opposite

charge?
Physics
1 answer:
Citrus2011 [14]3 years ago
6 0

Answer:

Opposite charge

Explanation:

The electric force between charged bodies at rest is conventionally called electrostatic force. Coulomb's law states the magnitude of electric force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between the charges.  According to Coulomb's law, if the two charges are q1 and q2 and the distance between the charges is ‘r’,  the force ‘F’ of attraction or repulsion between them is, then,  

                        F ∝ q₁q₂

and

                        F ∝ 1/ r²

Introducing constant of proportionality and combining the joint variation,

                        F = K \frac{q_{1}q_{2}}{r^{2}}  (Coulomb's law)

where k is 1/4πε₀ = 9 × 10⁹ Nm²/C²

Now let's apply Coulomb's law to solve the question.

Like charges attract while unlike charges repel. Since the two objects released from rest carry charges, the force between them is known as the electrostatic force. If the two objects released are assumed to be of equal quantity and of opposite charge, the two objects will attract thereby increasing the magnitude of the charges of the objects. When the magnitude of the charges increase, the electrostatic force of of the charges increase.    

You might be interested in
A photon has a wavelength of 500nm what is the energy associated
grigory [225]
Given: Plank's constant h = 6.626 x 10⁻³⁴ J.s   

           Speed of light c = 2.998 x 10⁸ m/s

            Wavelength  λ = 500 nm  convert to meter = 5 x 10⁻⁷ m

Required: Energy E =?

Formula: E = hc/λ

               E = (6.626 X 10⁻³⁴ J.s)(2.998 X 10⁸ m/s)/5 x 10⁻⁷ m

               E = 3.97 X 10⁻¹⁹ J  or in termS of electron volt

               E = 2.48 eV

               
8 0
3 years ago
A construction worker pushes a 25 kg load in a wheelbarrow for a distance of 5.0 m, using a horizontal force of 50.0 N. How much
aleksandrvk [35]

B. The amount of work done by the worker on the wheelbarrow is 250 J.

<h3>Work done by the worker</h3>

The amount of work done by the worker on the wheelbarrow is calculated as follows;

W = Fd

where;

  • F is applied force
  • d is displacement

W = 50 x 5

W = 250 J

Thus, the amount of work done by the worker on the wheelbarrow is 250 J.

Learn more about work done here: brainly.com/question/8119756

#SPJ1

6 0
2 years ago
You and your friend each drive 100.0 km. You travel at 30.0 km/h. Your friend travels at 45 km/h. How long will your friend be w
Ostrovityanka [42]

Answer:

See below

Explanation:

100 km / 45 km/hr = 2.222 hr

100 km / 30 km/hr =3.3333 hr

Difference = 1.111 hr  =   1 hr 6  2/3 min

7 0
2 years ago
Name a latitude where each of the following occurs polar easterlies, westerlies, and trade winds
Ad libitum [116K]
Polar easterlies:60-90 degrees
Westerlies: horse latitude
Trade winds: 30 degrees
7 0
3 years ago
A hollow spherical iron shell floats almost completely submerged in water. The outer diameter is 58.2 cm, and the density of iro
vredina [299]

Answer:

0.556m

Explanation:

unit conversion

58.2 cm = 0.582 m -> the outer radius is 0.582/2 = 0.291 m

7.87 g/cm^33 = 7.87 g/cm^33 * 1/1000 (kg/g) * 100^3 cm^3/m^3 = 7870 kg/m^3

Let r be the inner diameter we can find the volume of the hollow part of the sphere using the following formula

V_h = \frac{4}{3}\pi r^3

The volume of the iron shell is the volume of the whole sphere subtracted by volume of the hollow part

V_s = V - V_h = \frac{4}{3}\pi 0.291^3 - \frac{4}{3}\pi r^3 = \frac{4}{3}\pi(0.0246 - r^3)

Let water density \rho_w = 1000 kg/m^3, then the buoyant force is the weight of water displaced by the shell

F_b = g\rho_w V = g1000\frac{4}{3}\pi(0.291^3) = g1000\frac{4}{3}\pi(0.0246)

For the shell to almost completely submerged in water, its buoyant force equal to the weight of the shell

F_b = W_s

g1000\frac{4}{3}\pi(0.0246) = g\rho_sV_s

g1000\frac{4}{3}\pi(0.0246) = g7870\frac{4}{3}\pi(0.0246 - r^3)

1000*0.0246 = 7870(0.0246 - r^3)

24.6 = 193.602 - 7870r^3

r^3 = (193.602 - 24.6)/7870 = 0.02147

r = \sqrt[3]{0.02147} = 0.278 m

So the inner diameter is 0.278*2 = 0.556 m

3 0
3 years ago
Other questions:
  • The temperature &amp; pressure at which a solid becomes a liquid is called the
    12·1 answer
  • An 80 kg skateboarder moving at 3 m/s pushes off with her back foot to move faster.
    10·2 answers
  • Marta, Cato, and Juan plan a skit to illustrate one of the methods of charging.
    8·2 answers
  • A 12-volt car battery uses about 660 amps. How much power does it use?
    13·2 answers
  • Constant power P is delivered to a car of mass m by its engine. Show that if air resistance can be ignored, the distance covered
    8·2 answers
  • Two concurrent forces of 6 newtons and 12 newtons could produce the same effect as a single force of?
    5·2 answers
  • In the simulation above, as the projectile travels downward, how does the vertical velocity change?
    11·2 answers
  • A traffic accident detective measures the skid marks left by a car, 825kg. He determines that the distance between the point tha
    13·1 answer
  • A car starts from rest, speeds up with constant acceleration, and travels 350 meters in 5 seconds. What was the average velocity
    10·2 answers
  • How high up is a 3.00 kg object that has 300.j of energy
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!