Question

If the force magnitude increases when the objects are released and free to move, are the objects of the same charge or opposite charge?

Answer 1

Answer:

Opposite charge

Explanation:

The electric force between charged bodies at rest is conventionally called electrostatic force. Coulomb's law states the magnitude of electric force between two point charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between the charges.  According to Coulomb's law, if the two charges are q1 and q2 and the distance between the charges is ‘r’,  the force ‘F’ of attraction or repulsion between them is, then,  

                        F ∝ q₁q₂

and

                        F ∝ 1/ r²

Introducing constant of proportionality and combining the joint variation,

                        $F = K \frac{q_{1}q_{2}}{r^{2}}$  (Coulomb's law)

where k is 1/4πε₀ = 9 × 10⁹ Nm²/C²

Now let's apply Coulomb's law to solve the question.

Like charges attract while unlike charges repel. Since the two objects released from rest carry charges, the force between them is known as the electrostatic force. If the two objects released are assumed to be of equal quantity and of opposite charge, the two objects will attract thereby increasing the magnitude of the charges of the objects. When the magnitude of the charges increase, the electrostatic force of of the charges increase.