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3 years ago

10

A car starts from rest, speeds up with constant acceleration, and travels 350 meters in 5 seconds. What was the average velocity

of the car in m/s? 70 m/s omputer's answer now shown above.
What was the final velocity of the car (in m/s)?_______________ m/s Submit Answer Tries 0/2 Consider that the car started at rest.
What was the change in velocity of the car (in m/s)?________ m/s Submit Answer Tries 0/2
What was the acceleration of the car (in m/s2)? _______m/s2
Remember that the acceleration is the change in velocity divided by the change in time

2 answers:

larisa [96]3 years ago

5 0

Answer

70 m/s, 140 m/s, 28 m/s²

Explanation:

Average velocity = total distance travel / time = 350 / 5 = 70 m/s

average velocity = (initial velocity + final velocity) / 2

70 × 2 = 140 m/s

change in velocity = final velocity - initial velocity = 140 m/s - 0 = 140 m/s

acceleration = (final velocity - initial velocity) / t = 140 m/s / 5 = 28 m/s²

MissTica3 years ago

3 0

Answer:

1. Final velocity is 140m/s

2. Change in velocity is 140m/s

3. Acceleration is28m/s^2

Explanation:

Initial velocity u=0,

Distance travelled S=350m

Time taken t=5 seconds

The car move constant acceleration, then we can use any of equations of motion

v=u+at

v^2=u^2+2as

s=ut+(at^2)/2

Using equation 3

S=ut+(at^2)/2

350= 0×5+ (a ×5^2)/2

350= 0+(a×25)/2

350=25a/2

350×2=25a

700=25a

a=700/25

a=28m/s^2. Answer

1. Now, using equation 1

v=u+at

v=0+28×5

v=0+140

v=140m/s. Answer

2. The changed in the velocity of the car is final velocity minus the initial velocity

Change in velocity = v-u

Change in velocity = 140-0

Therefore,

Change in velocity is 140m/s. Answer

3. The acceleration has been answered before solving and it is

a= 28m/s^2

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