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Valentin [98]
3 years ago
6

Can anyone please help me on this question (DUE TOMORROW) (13 POINTS GO AWAY)

Physics
1 answer:
julia-pushkina [17]3 years ago
8 0

4.) Quantitative: notice the root word 'quantity', which is a certain percentage of something.

a.) Quantitative, since it represents a certain percentage. The weight before the camp could also be written as an improper fraction.

b.) This is also quantitative because it can be written as a ratio(2.99:500), which can also be written as a fraction(\frac{2.99}{500} or percentage.

c.) This is qualitative. Joan has a higher percentage than Emile.

d.) Qualitative. It judges the quality of something instead of amount. To make it quantitative requires a fraction of percentage. In this case, maybe you could add how he can run y miles every x seconds.

5.)

a.)This depends on whether or not the air is moving. If the classroom's AC is on, or the window is open, then the correct unit to use is CFM (cubic feet per minute). If not, the common unit is milliliters, but must also include temperature and air pressure as well as the volume of the room.

b.)  Simply calculate the volume of the can using inches cubed, since volume is the measure of how much space an object takes up.

c.) The unit would be \frac{kg}{ft^3}. If \frac{mass}{volume} = density, then simply multiply your density by your mass.

d.) I personally would use centimeters. Inches would work too, but centimeters would be much more accurate.

e.) Use the same formula for c.), which means kilograms per cubic foot.

Hope this helped.

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If he writes down "The distance between crests is 3 cm." 

That means he is describing the wavelength of a wave and not longitudinal wave. He ought to write something about " direction "

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if a tank filled with water contains a block and the height of the water above point A within the block is 0.6meter, what's the
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A 91.0-kg hockey player is skating on ice at 5.50 m/s. another hockey player of equal mass, moving at 8.1 m/s in the
never [62]

The momentum before the collision velocity after the collision will be 1237.6 kg m/s² and 6.8 m/sec.

<h3>What is the law of conservation of momentum?</h3>

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

The given data in the problem is;

(m₁) is the mass of hockey player 1= 91.0-kg

(m₂) is the mass of hockey player 2=  91.0-kg

(u₁) is the velocity before collision of hockey player 1 = 5.50 m/s.

(u₂) is the velocity before the collision of hockey player 2=?

a)

Momentum before the collision;

\rm  m_1u_1 + m_2u_2 \\\\ 91.0 \times 5.50 + 91.0 \times 8.1 \\\\ 1237.6 kg m/s^2

Momentum before the collision = 1237.6 kg m/s².

b)

The velocity of the two hockey players after the collision from the law of conservation of the momentum as:

Momentum before collision = Momentum after the collision

1237.6 kg m/s² = (m₁+m₂)V

1237.6 kg m/s² =(2 ×91.0-kg )V

V=6.8 m/sec.

Hence, momentum before the collision velocity after the collision will be 1237.6 kg m/s² and 6.8 m/sec.

To learn more about the law of conservation of momentum refer;

brainly.com/question/1113396

#SPJ1

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