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nasty-shy [4]
3 years ago
6

(d) Suppose two students are memorizing a list according to the same model dL dt = 0.5(1 − L) where L represents the fraction of

the list that is memorized at any time t. According to the uniqueness theorem, will the student who starts out knowing none of the list ever catch up to the student who knows one-third of the list? Explain.

Engineering
1 answer:
Neporo4naja [7]3 years ago
8 0

Answer:

Rate of learning =0

Explanation:

Please see attachment

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Vai trò của chủ đầu tư
White raven [17]

Answer:

can't understand the writting

4 0
3 years ago
Read 2 more answers
Copper spheres of 20-mm diameter are quenched by being dropped into a tank of water that is maintained at 280 K . The spheres ma
Ivenika [448]

Answer:

The height of the water is 1.25 m

Explanation:

copper properties are:

Kc=385 W/mK

D=20x10^-3 m

gc=8960 kg/m^3

Cp=385 J/kg*K

R=10x10^-3 m

Water properties at 280 K

pw=1000 kg/m^3

Kw=0.582

v=0.1247x10^-6 m^2/s

The drag force is:

F_{D} =\frac{1}{2} Co*p_{w} A*V^{2}

The bouyancy force is:

F_{B} =V*p_{w} *g

The weight is:

W=V*p_{c} *g

Laminar flow:

v_{T} =\frac{p_{c}-p_{w}*g*D^{2}   }{18*u} =\frac{(8960-1000)*9.8*(20x10^{-3})^{2}  }{18*0.00143} =1213.48 m/s

Reynold number:

Re=\frac{1000*1213.48*20x10^{-3} }{0.00143} \\Re>>1

Not flow region

For Newton flow region:

v_{T} =1.75\sqrt{(\frac{p_{c}-p_{w}  }{p_{w} })gD }=1.75\sqrt{(\frac{8960-1000}{1000} )*9.8*20x10^{-3} }  =2.186m/s

Re=\frac{1000*2.186*20x10^{-3} }{0.00143} =30573.4

Pr=\frac{\frac{u}{p} }{\frac{K}{pC_{p} } } =\frac{u*C_{p} }{k} =\frac{0.0014394198}{0.582} =10.31

Nu=2+(0.4Re^{1/2} +0.06Re^{2/3} )Pr^{2/5} (u/us)^{1/4} \\Nu=2+(0.4*30573.4^{1/2}+0.06*30573.4^{2/3}  )*10.31^{2/5} *(0.00143/0.00032)^{1/4} \\Nu=476.99

Nu=\frac{h*d}{K_{w} } \\h=\frac{476.99*0.582}{20x10^{-3} } =13880.44W/m^{2} K

\frac{T-T_{c} }{T_{w}-T_{c}  } =e^{-t/T} \\T=\frac{m_{c}C_{p}  }{hA_{c} } =\frac{8960*10x10^{-3}*385 }{13880.44*3} =0.828 s

e^{-t/0.828} =\frac{320-280}{360-280} \\t=0.573\\heightofthewater=2.186*0.573=1.25m

8 0
3 years ago
An assembly of positive and negative plates and separators in electrolyte is called what?
alexdok [17]

Answer:

  A battery

Explanation:

There are several words used to describe such an assembly:

  pile, battery, electrolytic cell

4 0
3 years ago
A 75 ! coaxial transmission line has a length of 2.0 cm and is terminated with a load impedance of 37.5 j75 !. If the relative p
Cerrena [4.2K]

Answer:

4.26

Explanation:

The wavelength λ is given by:

\lambda=v/f=c/nf\\c=speed\ of\ light=3*10^8m/s,f=frequency=3*10^9Hz,n=permittivity=2.56\\\\\lambda=3*10^8/(2.56*3*10^9)=0.0625\ m\\

Phase constant (β) = 2π/λ

βl = 2π/λ × l

l = 2 cm = 0.02 m

βl = 2π/0.0625 × 0.02=2.01 rad = 115.3°

1 rad = 180/π degrees

Z_L=load\ impedance=37.5+j75\\\\Z_o=characteristic impedance = 75\ ohm\\\\\tilde {Z_L}=Z_L/Z_o=37.5+j75/75=0.5+j

\tilde {Z_{in}}=\frac{\tilde {Z_{L}}+jtan\beta l}{1+j\tilde {Z_{L}}tan\beta l}=\frac{0.5+j+jtan(115.2)}{1+j(0.5+j)tan(115.2)}=0.253-j0.274\\  \\Z_{in}=Z_o\tilde {Z_{in}}=75(0.253-j0.274)=19-j20.5\\\\\Gamma_L=\frac{Z_L-Z_0}{Z_L+Z_o}=\frac{37.5+j75-75}{37.5+j75+75}=0.62\angle 83^o\\\\\Gamma_{in}=\frac{Z_{in}-Z_0}{Z_{in}+Z_o}=\frac{19-j20.5-75}{19-j20.5+75}=0.62\angle -147^o\\\\VSWR=\frac{1+\rho}{1-\rho} =\frac{1+0.62}{1-0.62}=4.26

6 0
3 years ago
A customer comes in with a vehicle that needs tire rotation and wheel alignment. Your bay has a two post frame engaging lift is
just olya [345]

Answer:

D

Explanation:

5 0
3 years ago
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