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Advocard [28]
3 years ago
7

Can someone help me with the physics problem?:

Physics
1 answer:
Mamont248 [21]3 years ago
6 0
The work you put into something is the energy it has afterward (neglecting friction and other so-called non-conservative forces).  This is called the work-energy theorem.  Think of objects in a gravitational field as "energy piggy banks".  If you put X joules of energy into it, that energy will be there as potential energy, stored for later.  So if you do 144J of work to elevate the bucket from an initial position, what ever it is initially, the final gravitational energy is 144J greater than before.
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The fictional rocket ship Adventure is measured to be 50 m long by the ship's captain inside the rocket.When the rocket moves pa
tensa zangetsu [6.8K]

Complete question:

Part A:) The fictional rocket ship Adventure is measured to be 50 m long by the ship's captain inside the rocket.When the rocket moves past a space dock at 0.5c , space-dock personnel measure the rocket ship to be 43.3 m long. The rocket ship Adventure travels to a star many light-years away, then turns around and returns at the same speed. When it returns to the space dock, who would have aged less: the space-dock personnel or ship's captain?

Part B: What is the momentum of a proton traveling at 0.62 c ?

Answer

a)Who would have aged less=The Captain would have aged less

b) p=3.96*10^{-19}kgm/s

Explanation:

From the question we are told that

Length measured by captain l_c=50m

Speed of rocket past tje space dock V=0.5c

Length measured by space-dock personnel l_c=43.3m

a)

Generally time moves slower when moving at speed of light, due to time dilation or variation.

Who would have aged less=The Captain would have aged less

b)

Generally the equation for Relativistic Momentum  is mathematically given as

p=\frac{m*v}{1 - v^2/c^2}

p=\frac{1.67*10^2-27*0.62*3.0*10^8)}{\sqrt{ 1 -0.6^2}}

p=3.96*10^{-19}kgm/s

3 0
3 years ago
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VashaNatasha [74]
Two half lives so it is 4000 years old
5 0
3 years ago
Read 2 more answers
When the distance between two charges is halved, the electrical force between them?
Llana [10]
If the distance between two charges is halved, the electrical force between them increases by a factor 4.

In fact, the magnitude of the electric force between two charges is given by:
F= k \frac{q_1 q_2}{r^2}
where
k is the Coulomb's constant
q1 and q2 are the two charges
r is the separation between the two charges

We see that the magnitude of the force F is inversely proportional to the square of the distance r. Therefore, if the radius is halved:
r'= \frac{r}{2}
the magnitude of the force changes as follows:
F'=k \frac{q_1 q_2}{r'^2}=k \frac{q_1 q_2}{( \frac{r}{2})^2 }=k \frac{q_1 q_2}{ \frac{r^2}{4} } =4k  \frac{q_1 q_2}{r^2}=4 F
so, the force increases by a factor 4.
3 0
3 years ago
Trên bóng đèn có ghi là 12v -6w. Khi đèn sáng bình thường thì dòng điện chạy qua đèn có cường độ là
Annette [7]

Answer:

Xin lỗi, ở đây không có ai nói tiếng Việt, nhưng bạn có thể cuộn hết cỡ xuống dưới để tìm một trang web cho não biết nói tiếng Việt

Explanation:

4 0
3 years ago
the gas in a balloon has P=100000 pa and v=0.0279 m^3. if the pressure increases to 120000 pa at constant temperature, what is t
mash [69]

Answer:

New volume of the baloon is 0.02325m^3

Explanation:

To answer this question we need to know the ideal gas law, which says:

p•V = n•R•T

p is pressure, V is volume, n is amount of substance (in moles), R is constant value and T is temperature.

Since it's stated that n and T are constant, and we know that R is a constant too, that means that p•V = constant value. Basically, that means that p1•V1 (pressure and volume before the pressure increase) equals to p2•V2 (pressure and volume after the pressure increase).

That means that:

100000 Pa • 0.0279 m^3 = 120000 Pa • V2. Next, V2= 100000•0.0279/120000. So, V2=0.02325m^3.

6 0
3 years ago
Read 2 more answers
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