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3 years ago

What is the molarity of a solution composed

Chemistry

1 answer:

Neporo4naja [7]3 years ago

7 0

Answer:

0.0845 M

Explanation:

First we convert 4.27 grams of potassium iodide into moles, using its molar mass:

Molar Mass of KI = 166 g/mol

4.27 g ÷ 166 g/mol = 0.0257 mol

Now we calculate the molarity of the solution, using the number of moles and the given volume:

Molarity = moles / liters

Molarity = 0.0257 mol / 0.304 L = 0.0845 M

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what is the specific heat of iron if 985 J of energy is required to raise the temperature of 158.5 g from 10.0°C to 24.0° C ?

Alexus [3.1K]

Answer: 0.44

Explanation:

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2 years ago

Calculate the wavelength, in nanometers, of the light emitted by a hydrogen atom when its electron fallsfrom the n = 7 to the n

Helga [31]

Answer:

λ=2167.6 nm

The wavelength of light emitted is 2167.6 nm.

Explanation:

We recall that Eₙ= $\frac{-2.18*10^{-18} J}{n^{2} }$

since there was transition from n7 to n=4 we will first calculate the change in the energy i.e ΔE

ΔE=E₄-E₇

ΔE= $-2.18*10^{-18} J(\frac{1}{4^{2} } -\frac{1}{7^{2} } )$

ΔE=-9.1760*10^-20 J

Now:

|ΔE|=Energy of photon=h*v=h*c/λ

λ=h*c/|ΔE|

λ= $\frac{6.63*10^{-34}J.s*3.00*10^{8}m/s }{9.1760*10^{-20} J }$

λ=2.1676*10^-6 m

λ=2167.6*10^-9 m

λ=2167.6 nm

The wavelength of light emitted is 2167.6 nm.

5 0

3 years ago

Explain why an insoluble compound added to water is considered a nonelectrolyte.

DaniilM [7]

Explanation:

A non-electrolyte is defined as a solution which does not contain any ions and hence, it is unable to conduct electricity.

For example, when a non-polar substance like $CCl_{4}$ is dissolved in water then it will not dissociate into ions.

As electricity is the flow of ions or electrons. So, a non-electrolyte solution is not able to conduct electricity.

Similarly, a compound that is insoluble in water will not dissociate into ions. Hence, this type of solution will not be able to conduct electricity.

8 0

2 years ago

Calculate Density: Volume=13cm3, Mass=147.55g Someone please help

almond37 [142]

Answer:

11.35 g/cm³

Explanation:

If your rounding then 11.4. hope this helps :)

5 0

2 years ago

If a buffer solution is 0.220 M in a weak acid ( Ka=7.4×10−5) and 0.540 M in its conjugate base, what is the pH?

valkas [14]

Answer: the pH of the solution is 4.52

Explanation:

Consider the weak acid as Ha, it is dissociated as expressed below

HA H⁺ + A⁻

the Henderson -Haselbach equation can be expressed as;

pH = pKa + log( [A⁻] / [HA])

the weak acid is dissociated into H⁺ and A⁻ ions in the solution.

now the conjugate base of the weak acid HA is

HA(aq) {weak acid} H⁺(aq) + A⁻(aq) {conjugate base}

so now we calculate the value of Kₐ as well as pH value by substituting the values of the concentrations into the equation;

pKₐ = -logKₐ

pKₐ = -log ( 7.4×10⁻⁵ )

pKₐ = 4.13

now thw pH is

pH = pKₐ + log( [A⁻] / [HA])

pH = 4.13 + log( [0.540] / [0.220])

pH = 4.13 + 0.3899

pH = 4.5199 = 4.52

Therefore the pH of the solution is 4.52

6 0

3 years ago