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4 years ago

6

Which of the following units would be the most appropriate for measuring the thickness of a piece of paper? A. centimeters B. mi

llimeters C. kilometers D. meters

1 answer:

Alla [95]4 years ago

3 0

B, millimeters because paper is really thin therefore it'd require small measurements for units.

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In your own words list the rules for naming hydrocarbons and substituted hydrocarbons. Be detailed in listing all rules includin

Irina18 [472]

Answer :

The basic rules for naming of hydrocarbons are :

First select the longest possible carbon chain.

The longest possible carbon chain should include the carbons of double or triple bonds.

The naming of alkane is done by adding the suffix -ane, alkene by adding the suffix -ene, alkyne by adding the suffix -yne.

The numbering is done in such a way that first carbon of double or triple bond gets the lowest number.

The carbon atoms of the double or triple bond get the preference over the other substituents present in the parent chain.

If two or more similar alkyl groups are present in a compound, the prefixes di-, tri-, tetra- and so on are used to specify the number of times of the alkyl groups in the chain.

8 0

4 years ago

An unknown element X has the following isotopes: ⁵²X (79.50% abundant), ⁴⁹X (8.00% abundant), ⁵⁰X (12.50% abundant). What is the

Verizon [17]

Answer:

51.51 amu .

Explanation:

The atomic mass 52 amu has percentage of 79.5%

The atomic mass 49 amu has percentage of 8%

The atomic mass 50 amu has percentage of 12.5 %

Average atomic pass will be weighted average of their atomic weights

= 52 x .795 + 49 x .08 + 50 x .125

= 41.34 + 3.92 + 6.25

= 51.51 amu .

4 0

3 years ago

a sample of 25.0g of an unknown metal is added to 25.0ml of water in a graduated cylinder and the final volume is 28.5ml what is

leva [86]

Answer:

<h2>The answer is 7.14 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question

mass of metal = 25 g

volume = final volume of water - initial volume of water

volume = 28.5 - 25 = 3.5 mL

It's density is

$density = \frac{25}{3.5} \\ = 7.142857...$

We have the final answer as

<h3>7.14 g/mL</h3>

Hope this helps you

8 0

3 years ago

A balance is best used to measure a sample's. which one is the right choice?

jekas [21]

C)mass is the correct answer

5 0

3 years ago

Read 2 more answers

If 45 g of O2 gas in a 500 mL container is exerting a pressure of 5.2 atm, what temperature is the gas?

iogann1982 [59]

If 45 g of O2 gas in a 500 mL container is exerting a pressure of 5.2 atm, 22.53K is the temperature in the gas.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

First, calculate the moles of the gas using the gas law,

PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 5.2 atm

V= 500 mL =0.5 L

n=?

R= $0.082057338 \;L \;atm \;K^{-1}mol^{-1}$

T=?

$Moles = \frac{mass}{molar \;mass}$

$Moles = \frac{45 g}{32}$

$Moles = \frac{45 g}{32}$

Moles = 1.40625

Putting value in the given equation:

$\frac{PV}{RT}=n$

$1.40625= \frac{5.2 \;atm\; X \;0.5 \;L}{0.082057338 \;L \;atm \;K^{-1}mol^{-1} X T}$

T= 22.53167034 K= 22.53K

Hence, If 45 g of O2 gas in a 500 mL container is exerting a pressure of 5.2 atm, 22.53K is the temperature in the gas.

Learn more about the ideal gas here:

brainly.com/question/27691721

#SPJ1

7 0

2 years ago