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Viktor [21]
3 years ago
6

A gas expands when 606 j of energy is added to it as heat. the expanding gas does 418 j of work on its surroundings.

Physics
2 answers:
KIM [24]3 years ago
6 0
A)
 Q=606 J 
<span> W = 418 J 
</span><span> From first law of thermodynamics, 
</span><span> [ Uf - Ui ] = Q - W 
</span><span> [ Uf - Ui ]=606 -418=188 J 
</span><span> [ Uf - Ui ]= 188 J 
</span><span> 
b )
 W2 = 1212 J 
</span><span> Q2 = ? 
</span><span> Ui2=Uf =Ui +188
</span><span> Uf2=Ui
</span> [ Uf2 - Ui2 ]<span>=Ui-(Ui+188)
</span><span> -188 J 
</span><span> Q2=W2+(Uf2 -Uf1) 
</span><span> Q2 =1212 -188=1024 J 
</span><span> Q added in second step (b) so that internal energy is equal to initial internal energy of step (a)=1024 J</span>

mylen [45]3 years ago
5 0
A) Heat added Q=606 J  
Work W = 418 J   
From first law of thermodynamics,  
 Change in internal energy [ Uf - Ui ] = Q - W  
 Change in internal energy [ Uf - Ui ]=606 -418=188 J 
 
 Change in internal energy [ Uf - Ui ]= 188 J  
 b ) work W2 = 1212 J  
 heat exchanged Q2 = ?  
 Initial energy of this process Ui2=Uf of previous=Ui +188 

 
 Final energy Uf2=initial energy of previous process=Ui  
 Change in internal energy of second process= [ Uf2 - Ui2 ] 
 
 Change in internal energy of second process=Ui-(Ui+188)  
 Change in internal energy of second process= -188 J  
 Q2=W2+(Uf2 -Uf1)  

 Q2 =1212 -188=1024 J
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Complete Question:

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