Answer:
Explanation: By using Gas Law, the new pressure can be calculated as follows:
Gas law states:
Using (1), and Identifying the knowns and unknowns, and plugging in (1) we get the following results:
Finally, the New pressure is calculated as follows:
When a pulse is palpated and counted, the pressure that would be a characteristic is : Sytolic
When your pulse is palpated and counted, you would feel the maximum pressure of your ventricle that you used to force the blood to travel throughout your body.
Answer:
C. Both Technicians A and B
Explanation:
To loosen a fastener immediately especially if it is a rusted one we can follow these steps.
1. Tap the sides of the fastener so that the rust particle fall off.
2. These rust particles can be brushed off.
3. Spray the fastener with the penetrating oil.
4. Again tap the sides with a hammer to let the oil penetrate the inter-locked parts (threads in case of a nut and bolt).
5. Loosen the fastener after oil has penetrated.
Note: It should be kept in consideration that spraying alone won't do the job, tapping is essential to let the oil penetrate deep in to free the rusted parts.
For this we want to use Boyle's Law. Boyle’s law states that the pressure and volume of a fixed quantity of a gas are inversely proportional under constant temperature conditions. The formula for this is P1V1 = P2V2. We want to solve this out so it equals V2 (Volume 2). So P1V1 / P2 = V2. Then plug in your values for the variables. So (101)(4.2) / 235 = V2; so 424.2 / 235 = V2. The final volume equals 1.81. I hope this helps, If not I am very sorry.
Answer:
Explanation:
In this problem we have three important moments; the instant in which the ball is released (1), the instant in which the ball starts to fly freely (2) and the instant in which has its maximum height (3). From the conservation of mechanical energy, the total energy in each moment has to be the same. In (1), it is only elastic potential energy; in (2) and (3) are both gravitational potential energy and kinetic energy. Writing this and substituting by known values, we obtain:
Since we only care about the velocity , we can keep only the second and third parts of the equation and solve:
So, the speed of the ball just after the launch is 17.3m/s.