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Ahat [919]
3 years ago
6

The solar noon solar radiation values at the top of the atmosphere above maun are 1366 wm−2 on february 2 and 1074 wm−2 on augus

t 2. why is solar receipt at the surface lower?
Physics
1 answer:
PilotLPTM [1.2K]3 years ago
8 0

You haven't stated any numbers showing that the intensity of solar radiation at the surface is lower than at the top of the atmosphere. Your data only show that the value at the top of the atmosphere is different on different dates.

From our vast experience, however, we do know that the solar intensity at the surface IS lower than it is at the top of the atmosphere, simply because the atmosphere absorbs some solar radiation ... different amounts of it at different wavelengths.

That's the main reason, for example, why the sky is red at sunrise and sunset and blue the rest of the day, and why the temperature of the air is so much higher than 3° absolute, and why we aren't broiled by X-rays all day. Also the reason why it's worth the tremendous cost and makes such a difference to build astronomical observatories on mountain tops and in low-Earth-orbit, instead of in convenient deep valleys.

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PSYCHO15rus [73]
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thus
25 = 1/2*10*t^2
50/10 = t^2
t = 2.23 seconds
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8 0
4 years ago
True or False: Graphs provide a good visual representation of the relationships between the factors investigated in an experimen
Alecsey [184]

Answer:

True

Explanation:

  • Yes, the graph provides a good visual representation of the relationship between the factors being investigated when there are only two variables being studied at a time.
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8 0
3 years ago
A budding magician holds a 2.24-mW laser pointer, wondering whether he could use it to keep an object floating in the air with t
Sonbull [250]

Answer:

 W = 1.49 10⁻¹¹ kg

Explanation:

For this problem, let's use Newton's equation of equilibrium

           F - W = 0

            F = W              (1)

Strength can be found from the definition of pressure

        P = F / A

        F = P A

   

The radiation pressure for a reflective surface is

            P = 2 I / c)

   

We substitute in equation 1

         2 I / c  A = W

The intensity is defined by the ratio of the power between the area

          I = P / A

          P = I A

We substitute

          2 P / c = W

   

           W = 2  2.24 10-3 / 3 108

           W = 1.49 10⁻¹¹ kg

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