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Nutka1998 [239]
2 years ago
8

Suppose a moving car has 2000 J of kinetic energy. If the carʹs speed doubles, how much kinetic energy would it then have?

Physics
1 answer:
Bond [772]2 years ago
8 0

Answer:

option A

Explanation:

given,

Kinetic energy of the car = 2000 J

speed of the car is doubled

we know,

KE_1 = \dfrac{1}{2}mv^2

2000= \dfrac{1}{2}mv^2........(1)

now, speed of the car is doubled

v' = 2 v

KE_2 = \dfrac{1}{2}mv'^2

KE_2 = \dfrac{1}{2}m(2v)^2

from equation (1)

KE_2 = 4\times \dfrac{1}{2}m(v)^2

KE_2 = 4\times 2000

KE_2 = 8000\ J

Hence, the Kinetic energy would be equal to 8000 J.

The correct answer is option A.

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