I’m not sure if this will help but I found: https://prezi.com/l0fa6du3b9kp/going-off-the-grid-assignment/?fallback=1 and
Answer:
Explanation:
Let the resistance of resistor be R .
Power of resistor V² / R , where V is potential applied .
V² / R = 100
120² / R = 100
R = 120² / 100
= 144 ohm .
Now potential diff applied = 220 V
current = potential diff / resistance
= 220 / 144
= 1.53 A approx .
Answer:
S=
2
1
gt
2
........(1)
And that of the other stone is
S=u(t−n)+
2
1
[g(t−n)
2
]........(2)
Since both the stones meet at the distance so equation (1)and equation(2) will be equal
2
1
gt
2
=u(t−n)+
2
1
[g(t−n)
2
]
gt
2
=2ut−2un+gt
2
+gn
2
−2gnt
t(2gn−2u)=gn
2
−2un
t=
(gn−u)
n(
2
gn
−u)
now putting value of t in equation(1)
s=
2
g
⎣
⎢
⎡
gn−u
2
[n(
2
gn
−u)]
⎦
⎥
⎤
2
S=
2
g
⎣
⎢
⎡
(gn−u)
2
n(
2
gn
−u)
⎦
⎥
⎤
Explanation:
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