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ella [17]
3 years ago
7

Plz answer this asap no explanation needed answer both questions first answer gets brainliest

Physics
1 answer:
Soloha48 [4]3 years ago
5 0

Answer:

8) d

9) c

<em>Hope this helps! :)</em>


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Can two people do different work, but have the same power?
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Yes, two people can do different work and have the same power.
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An electron is released from rest at the negative plate of a parallel plate capacitor. The charge per unit area on each plate is
dmitriy555 [2]

Answer:

v = 1.15*10^{7} m/s

Explanation:

given data:

charge/ unit area= \sigma = 1.99*10^{-7} C/m^2

plate seperation = 1.69*10^{-2} m

we know that

electric field btwn the plates isE = \frac{\sigma}{\epsilon}

force acting on charge is F = q E

Work done by charge q id\Delta X =\frac{ q\sigma \Delta x}{\epsilon}

this work done is converted into kinectic enerrgy

\frac{1}{2}mv^2 =\frac{ q\sigma \Delta x}{\epsilon}

solving for v

v = \sqrt{\frac{2q\Delta x}{\epsilon m}

\epsilon = 8.85*10^{-12} Nm2/C2

v = \sqrt{\frac{2 1.6*10^{-19}1.99*10^{-7}*1.69*10^{-2}}{8.85*10^{-12} *9.1*10^{-31}}

v = 1.15*10^{7} m/s

8 0
3 years ago
Explain how the perfume atomizer works under Bernoulli's principle
ss7ja [257]

Answer:

In an atomizer, or perfume sprayer, you squeeze a rubber bulb to squirt air through a tube. Because of the Bernoulli principle, the air rushing through the tube has a lower pressure than the surrounding atmosphere. ... The perfume is pushed out of the tube and sprays into the air as a fine mist.

Explanation:

4 0
3 years ago
Why the dust particles undergoes small random movements? <br><br> Plz help!!?
Rashid [163]
Brownian motion<span> or pedesis is the </span>random motion<span> of particles suspended in a fluid </span>
8 0
3 years ago
Solve the following two equations for the (positive) time, t, and the position, x. Assume SI units.
Luden [163]

A system of equations is a group of equations with the same variables that we need to solve simultaneously. Such that the solutions is given by the intersection betweens graphs of the functions.

We will see that the solution is (16.4, 807.0)

Here the system is:

x = 3.00*t^2\\x = 45.0*t + 69.0

To solve a system we usually need to isolate one of the variables in one equation and replace that in the other equation, here we already see that we have x isolated in the two equations, so we can write:

3.00*t^2 = x = 45.0*t + 69.0\\3.00*t^2 = 45.0*t + 69.0

Now we can solve the above equation for t:

3.00*t^2 = 45.0*t + 69.0\\\\3.00*t^2 - 45.0*t - 69.0 = 0

This is just a quadratic equation, the solution is given by the Bhaskara's formula, we will get:

t = \frac{-(-45.0) \pm \sqrt{(-45.0)^2 - 4*(3.00)*(-69.0)} }{2*3.00} \\\\t = \frac{{(45.0) \pm 53.4} }{6.00}

Then the two values of t are:

t = (45.0 + 53.4)/6 = 16.4

t = (45.0 - 53.4)/6 = -1.4

We want the positive solution, so we choose t = 16.4

To complete the solution we need to evaluate one of our functions in this time. Let's use the first one:

x = 45.0*16.4 + 69.0 = 807.0

Then the solution is:

(16.4, 807.0)

If you want to learn more you can read:

brainly.com/question/12895249

5 0
3 years ago
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