Plz answer this asap no explanation needed answer both questions first answer gets brainliest

A 5 inch tall balloon shoot doubles in height every 3 days. if the equation y=ab^x, where is x is the number of doubling periods

VashaNatasha [74]

In this item if we let x be the number of doubling period, that is number of days divided by 3, and y be the height of the bamboo shoot, in the equation
y = ab^x
The value of a is 5 because that is the original height of the shoot and b is 2 because we are talking about the doubling rate. The equation is therefore,
y = 5(2^x)

3 0

3 years ago

Two identical conducting spheres, fixed in place, attract each other with an electrostatic force of -0.2589 N when separated by

Harlamova29_29 [7]

Answer:

$q_1 = 7.19 \times 10^{-6} C$

$q_2 = -1.0 \times 10^{-6} C$

Explanation:

Let the initial charge on the two spheres are

$q_1, -q_2$

now we know that the force between them is given as

$F = \frac{kq_1q_2}{r^2}$

$0.2589 = \frac{kq_1q_2}{0.5^2}$

$q_1q_2 = 7.19 \times 10^{-12}$

now when two spheres are connected then final charge on them is given as

$q = \frac{q_1 - q_2}{2}$

now the force between them is given as

$0.3456 = \frac{k(q_1 - q_2)^2}{4(0.5)^2}$

now we have

$q_1 - q_2 = 6.19 \times 10^{-6}$

So by solving above two equations we have

$q_1 = 7.19 \times 10^{-6} C$

$q_2 = -1.0 \times 10^{-6} C$

3 0

3 years ago

A 30-m-long rocket train car is traveling from Los Angeles to New York at 0.5c when a light at the center of the car flashes. Wh

Novosadov [1.4K]

Given that,

Distance =30 m

speed = 0.5c

(A). We need to find the bell and siren simultaneous events for a passenger seated in the car

According to given data

The distance travelled by the light to reach either side of the rocket train car is same.

So, The two events are simultaneous and the bell and siren are the simultaneous events for a passenger seated in the car.

(B). We need to calculate time interval between the events

Using formula of time dilation

$\Delta t=\dfrac{\Delta t'}{\sqrt{1-\dfrac{v^2}{c^2}}}$ .....(I)

Where, $\delta t'$ = proper time

$\delta t$ = time interval between the events

The time interval between the events measured in a reference frame

The proper time in this case is

$\Delta t'=\Delta t_{1}-\dfrac{v\Delta x}{c^2}$

For the second interval,

Put the value of $\Delta t'$ in the equation (I)

$\Delta t_{2}=\dfrac{\Delta t_{1}-\dfrac{v\Delta x}{c^2}}{\sqrt{1-\dfrac{v^2}{c^2}}}$

Put the value in the equation

$\Delta t_{2} = \dfrac{0-\dfrac{0.5c\times30}{c^2}}{\sqrt{1-\dfrac{0.5^2c^2}{c^2}}}$

$\Delta t_{2}=\dfrac{-15}{3\times10^{8}\sqrt{1-0.25}}$

$\Delta t_{2}=-5.77\times10^{8}\ s$

Negative sign shows the siren rings before the bell ring.

Hence, (A). Yes, the bell and siren are simultaneous events.

(B). The siren sounds before the bell rings.

8 0

3 years ago

A 0.75 kilogram apple is thrown upward from the ground. The apple reaches a height of 5.5m, what is the beginning gravitational

MaRussiya [10]

Answer:

U(0.0m) = 0J

U(5.5m) = 40.42 J

Explanation:

The gravitational potential energy is given by the following formula:

$U=mgh$

h: height

m: mass of the apple = 0.75kg

g: gravitational acceleration = 9.8m/s^2

When the apple is at 5.5m from the ground the gravitational potential energy is:

$U=(0.75kg)(9.8m/s^2)(5.5m)=40.42\ J$

when the apple is on the ground you have:

$U=mg(0m)=0\ J$

6 0

3 years ago

Where would you expect to have more touch receptors: on the palm of your hand or on the back of your hand? Explain your reasonin

anygoal [31]

Answer:

ive answered this

Explanation:

please check your previose question

6 0

3 years ago