Answer:
Explanation:
Asúmase que la patinadora experimenta una aceleración constante. La fuerza neta experimentada por la patinadora:
What is the frequency of a wave having a period equal to 18 seconds? a. 6.6 × 10-2 hertz b. 5.5 × 10-2 hertz c. 3.3 × 10-2 hertz
2 answers:
Answer: Option (b) is the correct answer.
Explanation:
The time taken by a wave crest to travel a distance equal to the length of wave is known as wave period.
The relation between wave period and frequency is as follows.
where, T = time period
f = frequency
It is given that wave period is 18 seconds. Therefore, calculate the wave period as follows.
or,
=
= 0.055 per second (1 cycle per second = 1 Hertz)
or, f =
Thus, we can conclude that the frequency of the wave is .
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Answer:
a
The radial acceleration is
b
The horizontal Tension is
The vertical Tension is
Explanation:
The diagram illustrating this is shown on the first uploaded
From the question we are told that
The length of the string is
The mass of the bob is
The angle made by the string is
The centripetal force acting on the bob is mathematically represented as
Now From the diagram we see that this force is equivalent to
where T is the tension on the rope and v is the linear velocity
So
Now the downward normal force acting on the bob is mathematically represented as
So
=>
=>
The centripetal acceleration which the same as the radial acceleration of the bob is mathematically represented as
=>
substituting values
The horizontal component is mathematically represented as
substituting value
The vertical component of tension is
substituting value
The vector representation of the T in term is of the tension on the horizontal and the tension on the vertical is
substituting value
