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Answer:</em></u></h3><h3><u><em>
Ok, here we go...</em></u></h3><h3><u><em>
Explanation:</em></u></h3><h3><u><em>
Astronauts perform many tasks as they orbit Earth. The space station is designed to be a permanent orbiting research facility. Its major purpose is to perform world-class science and research that only a microgravity environment can provide. The station crew spends their day working on science experiments that require their input, as well as monitoring those that are controlled from the ground. They also take part in medical experiments to determine how well their bodies are adjusting to living in microgravity for long periods of time.</em></u></h3><h3><u><em>
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Working on the space station also means ensuring the maintenance and health of the orbiting platform. Crew members are constantly checking support systems and cleaning filters, updating computer equipment: doing many of the things homeowners must do to ensure their largest investment stays in good shape. Similarly, the Mission Control Center constantly monitors the space station and sends messages each day through voice or email with new instructions or plans to assist the crew members in their daily routines.</em></u></h3><h3><u><em>
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from the NASA website, COPYRIGHT Jun 8, 2015
<span>closing the switch completes the circuit</span>
Answer:
Power = 377.35 W or Power = 0.5065 hp
Explanation:
Given:
Number of steps, n = 1576
height of each step, h = 0.20 m
Total height achieved, H = nh = 1576 × 0.20 = 315.2 m
Mass of the runner, M = 70.0 kg
Total time taken, t = 9 minutes 33 seconds = (9 × 60) + 33 = 573 seconds
Now, the potential energy gained by the runner,
E = MgH
where, g is the acceleration due to the gravity
on substituting the values in the above formula, we get
E = 70 × 9.8 × 315.2
or
E = 216227.2 J
also,
Energy = Power × time
therefore,
Power = Energy/time
or
Power = 216227.2 J / 573
or
Power = 377.35 W
Now,
745 watt = 1 hp
or
1 watt = 1/745 hp
thus,
Power = 377.35 W = 337.35 × (1/745) hp
or
Power = 0.5065 hp
The answer to your question is capacitor :)
Answer:
A) I = Io 0.578, B) he light that leaves the polarized is completely polarized, being perpendicular to the axis of the second filter
Explanation:
A) Light passing through a polarizer must comply with the / bad law
I = Io cos2 tea
Where is at the angle of the polarizer and incident light
I = Io cos2 45
I = Io 0.578
Therefore the beam intensity is 0.578 of the incident intensity
.B) the light that leaves the polarized is completely polarized, being perpendicular to the axis of the second filter