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Nadya [2.5K]
3 years ago
9

Find the inverse of 3x+8

Mathematics
1 answer:
Margarita [4]3 years ago
4 0
Try -3x-8   hope that helps

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Laura and Chase wants to go to a baseball game. But, the tickets cost $300 each. Laura only had $20 left because she went shoppi
Natalija [7]

Answer:

No they don’t have enough money

Step-by-step explanation:

No:

54+20=74=that’s not enough

211+189=400

Thats enough but they’re are two of them so it would only be enough for one of them

I HOPE THIS IS WHAT YOU’RE LOOKING FOR AND IF NOT THEN I’M SO SO SORRY

5 0
3 years ago
In right triangle abc /_B is right angle and m/_c=30 if Ac=10 what is AB
Ivanshal [37]

Answer:

plz mark brainliest..

Step-by-step explanation:

AC is the hypotenuse = 10

AB is side opposite to <C

<C = 30°, <B = 90°

by 30°-60°-90° theorem

side opposite to 30° is equal to half of hypotenuse

therefore,

AB = 1/2 × AC

AB = 1/2 × 10

AB = 5

therefore number 5 is answer

hope it will help you

7 0
3 years ago
FIND 2 EQUIVALENT FORMS FOR EACH FRACTION USING MULTIPLICATION AND DIVISION. 8/12,6/8,9/15,2/16
Alja [10]
8/12: 2/3 and 16/24
6/8: 3/4 and 12/16
9/15: 3/5 and 18/30
2/16: 1/8 and 4/32

5 0
3 years ago
Read 2 more answers
I need my smart homies to answer this question for me !
ella [17]

Answer:

Part A: chosen method is by factoring

Part B: First rewrite the equation by writing -24 as a difference so you get     x² -9x - 15x + 135 = 0. Then factor out the x and the -15 from the equation so you get x(x-9) - 15(x-9) = 0. Then factor out x-9 from the equation so you have (x-9)(x-15) = 0. Finally, set each expression to 0: x-9=0 and x-15=0 and then solve: x=9 and x=15

Part C: x=9, x=15

4 0
3 years ago
PLEASEEE HURRYYY
Masteriza [31]

Answer:

(2,-5) and (2,1).

Step-by-step explanation:

We need to find the find all the points having an x coordinate of 2 whose distance from the point (-2,-4) is 5.

A circle with center (-2,-4) and radius 5 represents all the points whose distance from the point (-2,-4) is 5.

Standard form of a circle is

(x-h)^2+(y-k)^2=r^2

where, (h,k) is center and r is the radius.

(x-(-2))^2+(y-(-4))^2=(5)^2

(x+2)^2+(y+2)^2=25

Now, put x=2.

(2+2)^2+(y+2)^2=25

(4)^2+(y+2)^2=25

(y+2)^2=25-16

(y+2)^2=9

Taking square root on both sides.

y+2=\pm\sqrt{9}

y+2=\pm3

y+2=-3\text{ or }y+2=3

y=-5\text{ or }y=1

So, the y-coordinates of the points are -5 and 1.

Therefore, the required points are (2,-5) and (2,1).

8 0
3 years ago
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