Answer:
The mean free path = 2.16*10^-6 m
Explanation:
<u>Given:</u>
Pressure of gas P = 100 kPa
Temperature T = 300 K
collision cross section, σ = 2.0*10^-20 m2
Boltzmann constant, k = 1.38*10^-23 J/K
<u>To determine:</u>
The mean free path, λ
<u>Calculation:</u>
The mean free path is related to the collision cross section by the following equation:

where n = number density

Substituting for P, k and T in equation (2) gives:

Next, substituting for n and σ in equation (1) gives:

The little number at the top of the element
Answer:
.000064565
Explanation:
H3O+=10^-pH
- Hope that helps! Please let me know if you need further explanation.
Answer:
Explanation:
1 x 10²³ molecules of methane
6.02 x 10²³ molecules of methane = 1 mole of methane
10²³ molecules of methane = 1 / 6.02 moles of methane
= .166 moles .