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andriy [413]
3 years ago
11

A helium balloon can hold about 6.8 mol of the gas. Assuming the balloon is kept at room temperature (25°C) and had a maximum of

1.2L, what is the pressure inside teh balloon
Chemistry
2 answers:
Kipish [7]3 years ago
6 0

Answer:

P= 138.6 atm or 1.4x10²

Explanation:

You will need to use PV=nRT to solve for P, pressure

Where the R constant is  0.08206 L atm mol^-1 K^-1

V is 1.2 L

T is temperature in kelvin, 273.15+25= 298.15

n is 6.8 mol

P*1.2=6.8*0.08206*298.15 ---> P*1.2=166.3700852 ---> P=166.3700852/1.2

P=138.6 atm

or 1.4x10²

Elza [17]3 years ago
3 0

Answer:

138.47atm

Explanation:

Data obtained from the question include:

n (number of mole) = 6.8 mol

T (temperature) = 25°C = 25 + 273 = 298K

V (volume) = 1.2L

R (gas constant) = 0.082atm.L/Kmol

P (pressure) =?

Using the ideal gas equation PV = nRT, we can confidently calculate the pressure inside the balloon as shown below:

PV = nRT

P = nRT/V

P = (6.8 x 0.082 x 298)/1.2

P = 138.47atm

Therefore, the pressure inside the balloon is 138.47atm

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The volume occupied by the gas in the container is 1 m³

Boyles law applies

P₁ V₁ = P₂ V₂

Where P₁ = 200kpa

P₂ = 300kpa

if its initial volume is 1.5

then,

P₁ V₁ = P₂ V₂

200 × 1.5 = 300 × V₂

V₂ = 200 × 1.5 / 300

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Hence  the volume occupied by the gas container is 1 m³

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4 0
2 years ago
A mixture of reactants and products for the reaction shown below is at
zavuch27 [327]

If the volume of the container were increased to 4.0 L, more N₂ and H₂ would be produced (Option D)

<h3>What is chemical equilibrium? </h3>

This is simply defined as a state in a chemical system where there is no observable change in the properties of the system with time.

<h3>Principle of chemical equilibrium </h3>

A French scientist postulated a principle which helps us to understand a chemical system in equilibrium.

The principle states as follow:

If a an external constraint such as change in temperature, pressure or concentration is imposed on a system in equilibrium, the equilibrium will shift so as to neutralize the effect.

<h3>How to determine what will happen if the volume of the container is increased from 2 L to 4 L</h3>

From the principle given above, we can see that volume does not affect equilirium position.

However, from Boyle's law, we understood that pressure and volume are in invest relationship.

Thus, increasing volume simply means decreasing pressure.

A decrease in pressure will favors the side where there is an increase in volume.

Let us consider the equation from the question:

N₂(g) + 3H₂(g) <=> 2NH₃(g)

  • Volume of reactants = 1 + 3 = 4 L
  • Volume of products = 2 L

Thus, we can conclude that increasing the volume (i.e decreasing the pressure) of the reaction will favors the backward reaction, hence, more N₂ and H₂ would be produced.

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5 0
2 years ago
A photon of light possesses 5 x 10^-19 J of energy. Calculate its frequency
saveliy_v [14]

Answer:

The frequency of photon is 0.75×10¹⁵ s⁻¹.

Explanation:

Given data:

Energy of photon = 5×10⁻¹⁹ J

Frequency of photon = ?

Solution:

Formula;

E = hf

h = planck's constant = 6.63×10⁻³⁴ Js

5×10⁻¹⁹ J =  6.63×10⁻³⁴ Js ×f

f =  5×10⁻¹⁹ J / 6.63×10⁻³⁴ Js

f = 0.75×10¹⁵ s⁻¹

The frequency of photon is 0.75×10¹⁵ s⁻¹.

4 0
3 years ago
A gas has a volume of 30 L at 105 kPa. What pressure is required to compress the gas to 21 L?
Aloiza [94]

Answer: 150 kPa

Explanation:

Given that,

Original volume of gas V1 = 30L

Original pressure of gas P1 = 105 kPa

New pressure of gas P2 = ?

New volume of gas V2 = 21L

Since pressure and volume are given while temperature is constant, apply the formula for Boyle's law

P1V1 = P2V2

105 kPa x 30L = P2 x 21L

3150 kPa L = P2 x 21L

P2 = 3150 kPa L / 21 L

P2 = 150 kPa

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8 0
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Consider the nuclear equation below. Superscript 22 subscript 11 upper N a right arrow superscript 22 subscript 10 upper N e plu
natali 33 [55]

Answer:

+1

Explanation:

For the equation to be balanced, the total mass number and the total atomic number on both side of the equation but be equal.

This is illustrated:

For the mass number:

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Right side: 22 + 0 = 22

For the atomic number:

Left side: 11

Right side: 10 + x

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Collect like terms

x = 11 - 10

x = 1

See attachment for further explanation.

8 0
3 years ago
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