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andriy [413]
3 years ago
11

A helium balloon can hold about 6.8 mol of the gas. Assuming the balloon is kept at room temperature (25°C) and had a maximum of

1.2L, what is the pressure inside teh balloon
Chemistry
2 answers:
Kipish [7]3 years ago
6 0

Answer:

P= 138.6 atm or 1.4x10²

Explanation:

You will need to use PV=nRT to solve for P, pressure

Where the R constant is  0.08206 L atm mol^-1 K^-1

V is 1.2 L

T is temperature in kelvin, 273.15+25= 298.15

n is 6.8 mol

P*1.2=6.8*0.08206*298.15 ---> P*1.2=166.3700852 ---> P=166.3700852/1.2

P=138.6 atm

or 1.4x10²

Elza [17]3 years ago
3 0

Answer:

138.47atm

Explanation:

Data obtained from the question include:

n (number of mole) = 6.8 mol

T (temperature) = 25°C = 25 + 273 = 298K

V (volume) = 1.2L

R (gas constant) = 0.082atm.L/Kmol

P (pressure) =?

Using the ideal gas equation PV = nRT, we can confidently calculate the pressure inside the balloon as shown below:

PV = nRT

P = nRT/V

P = (6.8 x 0.082 x 298)/1.2

P = 138.47atm

Therefore, the pressure inside the balloon is 138.47atm

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1.

V = 200 mL (volume)

c = 3 M = 3 mol/L (concentration)

First we convert mL to L:

200 mL = 0.2 L

Then we calculate the moles using the formula: n = V × c = 0.2 L × 3 mol = 0.6 mol

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