Answer: The final temperature of the gas is 7.58 °C.
Explanation: We are given initial and final pressure of the system and we need to find the final temperature of the system.
To calculate it, we use the equation given by Gay-Lussac.
His law states that pressure is directly related to the temperature of the gas.
Or,
where,
= initial pressure = 893 mmHg = 1.175atm (Conversion factor: 1atm = 760mmHg)
= initial temperature = 49.3°C = [49.3 + 273.15]K = 322.45K
= Final pressure = 778mmHg = 1.023atm
= Final temperature = ?°C
Putting values in above equation, we get:
Converting Final temperature from kelvin to degree Celsius.
![T_2=280.73K=[280.73-273.15]^oC=7.58^oC](https://tex.z-dn.net/?f=T_2%3D280.73K%3D%5B280.73-273.15%5D%5EoC%3D7.58%5EoC)
Hence, the final temperature of the gas is 7.58 °C.
<span>From the Born–Landé equation the lattice energy U ∝ (Z+ × Z-) / (r+ + r-) where Z+ and Z- are the charges on the cation and anion, respectively; r+ and r- are radii of the cation and anion, respectively.
The Z+×Z- term dominates. MgO has 2×2 (4) so it will have the higher U than Li2O Z+ × Z- = 2.
You only consider (r+ + r-) term when the Z+×Z- term is the same; smallest the (r+ + r-), the larger is the U.
U(MgO) = 3795 </span>kJ mol^-1
<span>U(Li2O) = 2799 kJ mol^-1
MgO has larger.
</span>
Answer:
They have no solid surface.
Explanation:
Many outer planets are actually known as gas giants and don't contain much of a solid surface. hope this helped!
The answer is (D) microscopic. You can remember this, because the name is very close to "microscope," an instrument used to greatly magnify and observe tiny organisms and objects.
