5 L = 6.0 * 10^10
I believe.
<span> There are 97.2 mol of O in 10.8 mol of Fe(NO3)3</span>
<u>Answer:</u> The energy released in the given nuclear reaction is 1.3106 MeV.
<u>Explanation:</u>
For the given nuclear reaction:

We are given:
Mass of
= 39.963998 u
Mass of
= 39.962591 u
To calculate the mass defect, we use the equation:

Putting values in above equation, we get:

To calculate the energy released, we use the equation:

(Conversion factor:
)

Hence, the energy released in the given nuclear reaction is 1.3106 MeV.