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Phantasy [73]
3 years ago
14

Write the ksp expression for the sparingly soluble compound silver chromate, ag2cro4.

Chemistry
1 answer:
Sladkaya [172]3 years ago
4 0
Chemical reaction (dissociation) of silver chromate in water:
Ag₂CrO₄(s) → 2Ag⁺(aq) + CrO₄²⁻(aq).<span>
Ksp(</span>Ag₂CrO₄) = [Ag⁺]²·[CrO₄²⁻].<span>
[</span>CrO₄²⁻] = x.<span>
[</span>Ag⁺] = 2[CrO₄²⁻] = 2x<span>
Ksp = (2x)</span>² · x = 4x³.
Ksp is the solubility product constant <span>for a solid substance dissolving in an aqueous solution.</span>
[Ag⁺] is equilibrium concentration of silver cations.
[CrO₄²⁻] is equilibrium concentration of chromate anions.

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