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morpeh [17]
3 years ago
13

A _______ is a repeating disturbance or vibration that transfers or moves energy from place to place without transporting mass.

Physics
2 answers:
cupoosta [38]3 years ago
7 0

the answer is a wave


LiRa [457]3 years ago
3 0

Answer:

The Answer is <u>WAVE</u>

Explanation:

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A source emits monochromatic light of wavelength 495 nm in air. when the light passes through a liquid, its wavelength reduces t
Katyanochek1 [597]
By definition, the refractive index is
n = c/v
where c =  3 x 10⁸ m/s,  the speed of light in vacuum
v = the speed of light in the medium (the liquid).

The frequency of the light source is
f = (3 x 10⁸ m/s)/(495 x 10⁻⁹ m) = 6.0606 x 10¹⁴ Hz

Because the wavelength in the liquid is 434 nm = 434 x 10⁻⁹ m, 
v = (6.0606 x 10¹⁴ 1/s)*(434 x 10⁻⁹ m) = 2.6303 x 10⁸ m/s

The refractive index is (3 x 10⁸)/(2.6303 x 10⁸) = 1.1406

Answer:  a.  1.14
6 0
3 years ago
If a question asks about velocity in a projectile, is it referring to the vertical or horizontal velocity? An example where this
deff fn [24]

Explanation:

If it doesn't specify vertical or horizontal, that means it wants you to find the total velocity.  You can do that using Pythagorean theorem:

v² = vₓ² + vᵧ²

3 0
3 years ago
Two mirrors are at right angles to one another. A light ray is incident on the first at an angle of 30° with respect to the norm
marta [7]

Answer:

reflected angle - secod mirror = 60°

Explanation:

I attached an image with the solution to this problem below.

In the solution the reflection law, incident angle = reflected angle, is used. Furthermore some trigonometric relation is used.

You can notice in the image that the angle of reflection in the second mirror is 60°

7 0
3 years ago
A voltage amplifier with an input resistance of 40k ohms, an output resistance of 100 ohms, and a gain of 300 V/V is connected b
AfilCa [17]

Answer:

89.45 v/v

Explanation:

Let's take the data:

First draw the amplifier circuit.

After the circuit, the voltage division rule can be used to compute the parameters:

The input section is computed like this: \frac{R_{in} }{(R_{sig}  + R_{in} }  (v_{sig})

The output section is computed like this R_{L}/ (R_out}  + R_{in} )

The product AV_{in} V_{out} gives

AV_{in} V_{out}  = A×\frac{R_{in} }{(R_{sig}  + R_{in} }  (v_{sig})×R_{L}/ (R_out}  + R_{in} )

Computing gives output voltage = 89.45 v/v

5 0
3 years ago
PLS ANSWER ASAP
TiliK225 [7]

Answer: Answer is D

I took the test little while back.

3 0
3 years ago
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