By definition, the refractive index is
n = c/v
where c = 3 x 10⁸ m/s, the speed of light in vacuum
v = the speed of light in the medium (the liquid).
The frequency of the light source is
f = (3 x 10⁸ m/s)/(495 x 10⁻⁹ m) = 6.0606 x 10¹⁴ Hz
Because the wavelength in the liquid is 434 nm = 434 x 10⁻⁹ m,
v = (6.0606 x 10¹⁴ 1/s)*(434 x 10⁻⁹ m) = 2.6303 x 10⁸ m/s
The refractive index is (3 x 10⁸)/(2.6303 x 10⁸) = 1.1406
Answer: a. 1.14
Explanation:
If it doesn't specify vertical or horizontal, that means it wants you to find the total velocity. You can do that using Pythagorean theorem:
v² = vₓ² + vᵧ²
Answer:
reflected angle - secod mirror = 60°
Explanation:
I attached an image with the solution to this problem below.
In the solution the reflection law, incident angle = reflected angle, is used. Furthermore some trigonometric relation is used.
You can notice in the image that the angle of reflection in the second mirror is 60°
Answer:
89.45 v/v
Explanation:
Let's take the data:
First draw the amplifier circuit.
After the circuit, the voltage division rule can be used to compute the parameters:
The input section is computed like this: 
The output section is computed like this 
The product A
gives
A
= A×
×
Computing gives output voltage = 89.45 v/v
Answer: Answer is D
I took the test little while back.