I think it’s c but I could be wrong
Answer:
<em>it's</em> <em>quickly moved</em>
Explanation:
<em>whisk
</em>
<em>/(h)wisk/
</em>
<em>Learn to pronounce
</em>
<em>verb
</em>
<em>past tense: whisked; past participle: whisked
</em>
<em />
<em>take or move (someone or something) in a particular direction suddenly and quickly.</em>
<em />
<em>Hope this helps ^^</em>
Answer:
I think the answer is X if wrong i´m sorry
Explanation:
Answer:
Reaction 1: Kc increases
Reaction 2: Kc decreases
Reaction 3: The is no change
Explanation:
Let us consider the following reactions:
Reaction 1: A ⇌ 2B ΔH° = 20.0 kJ/mol
Reaction 2: A + B ⇌ C ΔH° = −5.4 kJ/mol
Reaction 3: 2A⇌ B ΔH° = 0.0 kJ/mol
To predict what will happen when the temperature is raised we need to take into account Le Chatelier Principle: when a system at equilibrium suffers a perturbation, it will shift its equilibrium to counteract such perturbation. This means that <em>if the temperature is raised (perturbation), the system will react to lower the temperature.</em>
Reaction 1 is endothermic (ΔH° > 0). If the temperature is raised the system will favor the forward reaction to absorb heat and lower the temperature, thus increasing the value of Kc.
Reaction 2 is exothermic (ΔH° < 0). If the temperature is raised the system will favor the reverse reaction to absorb heat and lower the temperature, thus decreasing the value of Kc.
Reaction 3 is not endothermic nor exothermic (ΔH° = 0) so an increase in the temperature will have no effect on the equilibrium.
