Hello here
It means that a person has the ability to describe, explain, and predict natural phenomena.
Answer:
Explanation:
Force on a moving charge is given by the following relation
F = q ( v x B )
for proton
q = e , v = vi , B = Bk
F = e ( vi x Bk )
= Bev - j
= - Bevj
The direction of force is along negative of y axis or -y - axis.
for electron
q = - e , v = vi , B = Bk
F = - e ( vi x Bk )
= - Bev - j
= Bevj
The direction of force is along positive of y axis or + y - axis.
Answer:

Explanation:
As the path is straight, so the speed is equivalent to velocity. Now. assuming that the acceleration and deceleration of the train are constant. So, change of velocity with respect to time for acceleration as well as deceleration is constant. Hence, the slope of the speed-time graph is constant for the time of acceleration as well as deceleration. The speed for the time from
to
is constant, so slope for this interval of time is zero. The speed-time graph is shown in the figure.
The total distance covered by the train during the entire journey is the area of the speed-time graph.
Area


As velocity is in
and time is in
so the unit of area is 
Hence, the total distance is
.
Answer:
50.4÷1.18= 42.7m/s as speed is equal to the distance over the time taken
Answer:
Total mechanical energy is the sum of potential energy plus kinetic energy. The kinetic energy will be 250 [J] and the potential energy is zero, therefore Total mechanical energy will be 250 + 0 =250[J]
Explanation:
This is a problem that applies the principle of energy conservation, i.e. mechanical energy that will be transformed into kinetic energy. We need to identify what kind of energy we have depending on the position of the ball with respect to the reference axis we take.
The reference axis or reference point is the point at which the potential energy is equal to zero, for this case we will take the ground as our reference point.
We know that the potential energy is defined by:
![E_{p}=m*g*h\\ where:\\m=mass[kg]\\g=gravity[m/s^2]\\h=elevation[m]](https://tex.z-dn.net/?f=E_%7Bp%7D%3Dm%2Ag%2Ah%5C%5C%20where%3A%5C%5Cm%3Dmass%5Bkg%5D%5C%5Cg%3Dgravity%5Bm%2Fs%5E2%5D%5C%5Ch%3Delevation%5Bm%5D)
We can clear the mass from this equation:
![m=\frac{E_{p} }{(g*h)} \\m=\frac{250 }{(9.81*5)} \\\\m=5.09[kg]](https://tex.z-dn.net/?f=m%3D%5Cfrac%7BE_%7Bp%7D%20%7D%7B%28g%2Ah%29%7D%20%5C%5Cm%3D%5Cfrac%7B250%20%7D%7B%289.81%2A5%29%7D%20%5C%5C%5C%5Cm%3D5.09%5Bkg%5D)
When this body falls its potential energy will decrease but its kinetic energy will increase and reach its maximum value when the ball reaches the ground.
In such a way that its potential energy would be transformed into kinetic energy.
![E_{k} = E_{p} \\E_{k} =kinetic energy [J]](https://tex.z-dn.net/?f=E_%7Bk%7D%20%3D%20E_%7Bp%7D%20%5C%5CE_%7Bk%7D%20%3Dkinetic%20energy%20%5BJ%5D)
Since the potential energy has been transformed all into kinetic energy the amount of energy is conserved, therefore the total mechanical energy will remain the same.