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4 years ago

What is the mass of a crate if a force of 200 N causes t to accelerate at 8 ms? (Formula F=ma)

2 answers:

6 0

Hey there! :D

Plug in what you know.

F=ma

F= force m= mass a= acceleration

200 N= m*8 ms

Divide both sides by 8.

m= 25

The mass is 25.

I hope this helps!
~kaikers

Elden [556K]4 years ago

6 0

Here's what you know:
F = 200 N
a = 8 m/s^2

now, plug those numbers into the formula (f=ma) to get:
200 = m(8)

to solve for m, divide both sides by 8
Answer: 25

hope i helped :3

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1. Una carga eléctrica de 5*10-6 C genera un campo eléctrico a su alrededor. Calcula la intensidad de este campo a una distancia

Jlenok [28]

Answer:

La intensidad del campo eléctrico es 70312.5 $\frac{N}{C}$ .

Explanation:

La perturbación que crea en torno a ella una carga eléctrica se representa mediante un vector denominado campo eléctrico.

Se dice que un campo eléctrico es uniforme en una región del espacio cuando la intensidad de dicho campo eléctrico es el mismo en todos los puntos de dicha región.

El campo eléctrico E creado por la carga puntual q en un punto cualquiera P se define como:

$E=k*\frac{q}{r^{2} }$

donde q es la carga creadora del campo, k es la constante electrostática y r es la distancia desde la carga fuente al punto P.

En este caso, los datos son:

k= 9*10⁹ $\frac{N*m^{2} }{C^{2} }$
q= 5*10⁻⁶ C
r= 0.8 m

Reemplazando:

$E=9*10^{9}\frac{N*m^{2} }{C^{2} } *\frac{5*10^{-6} C}{(0.8 m)^{2} }$

Resolviendo:

E= 70312.5 $\frac{N}{C}$

La intensidad del campo eléctrico es 70312.5 $\frac{N}{C}$ .

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3 years ago

An air-standard Diesel cycle has a compression ratio of 16 and a cutoff ratio of 2. At the beginning of the compression process,

Sedbober [7]

Answer:

$a.T_3=1723.8kPa\\b.n=0.563\\c.MEP=674.95kPa$

Explanation:

a. Internal energy and the relative specific volume at $s_1$ are determined from A-17: $u_1=214.07kJ/kg, \ \alpha_r_1=621.2$ .

The relative specific volume at $s_2$ is calculated from the compression ratio:

$\alpha_r_2=\frac{\alpha_r_1}{r}\\=\frac{621.2}{16}\\=38.825$

#from this, the temperature and enthalpy at state 2, $s_2$ can be determined using interpolations $T_2=862K$ and $h_2=890.9kJ/kg$ . The specific volume at $s_1$ can then be determined as:

$\alpha_1=\frac{RT_1}{P_1}\\\\=\frac{0.287\times 300}{95} m^3/kg\\0.906316m^3/kg$

Specific volume, $s_2$ :

$\alpha_2=\frac{\alpha_1}{r}\\=\frac{0.906316}{16}m^3/kg\\=0.05664m^3/kg$

The pressures at $s_2 \ and\ s_3$ is:

$P_2=P_3=\frac{RT_2}{\alpha_2}\\\\=\frac{0.287\times862}{0.05664}\\=4367.06kPa$

.The thermal efficiency=> maximum temperature at $s_3$ can be obtained from the expansion work at constant pressure during $s_2-s_3$

$\bigtriangleup \omega_2_-_3=P(\alpha_3-\alpha_2)\\R(T_3-T_2)=P\alpha(r_c-1)\\T_3=T_2+\frac{P\alpha_2}{R}(r_c-1)\\\\=(862+\frac{4367\times 0.05664}{0.287}(2-1))K\\=1723.84K$

b.Relative SV and enthalpy at $s_3$ are obtained for the given temperature with interpolation with data from A-17 : $a_r_3=4.553 \ and\ h_3=1909.62kJ/kg$

Relative SV at $s_4$ is

$a_r_4=\frac{r}{r_c}\alpha _r_3$

= $=\frac{16}{2}\times4.533\\=36.424$

Thermal efficiency occurs when the heat loss is equal to the internal energy decrease and heat gain equal to enthalpy increase;

$n=1-\frac{q_o}{q_i}\\=1-\frac{u_4-u_1}{h_3-h_2}\\=1-\frac{65903-214.07}{1909.62-890.9}\\=0.563$

Hence, the thermal efficiency is 0.563

c. The mean relative pressure is calculated from its standard definition:

$MEP=\frac{\omega}{\alpa_1-\alpa_2}\\=\frac{q_i-q_o}{\alpha_1(1-1/r)}\\=\frac{1909.62-890.9-(65903-214.7)}{0.90632(1-1/16)}\\=674.95kPa$

Hence, the mean effective relative pressure is 674.95kPa

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3 years ago

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Answer:

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If the acceleration is zero Fs = M g and the scale reads the persons weight

If the elevator is decelerating then au is negative and the scale reading Fs = (g - au) M and the scale reading is less than the weight of the person

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2 years ago

Need help with my science quiz

MaRussiya [10]

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3 years ago

A rocket, initially at rest on the ground, accelerates straight upward from rest with constant acceleration 44.1m/s^2 . The acce

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The acceleration and distance is related to the following expression:
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3 years ago