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Harman [31]
3 years ago
13

Muscles that are fatigued ____.

Physics
1 answer:
ankoles [38]3 years ago
3 0

Answer: Muscles that are fatigued <u>WEAK.</u>

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A mailman performed 588J of work lifting a box 1.4 m. How much force did the mailman use?
lord [1]

As we know that work done due a force F is given by formula

W = F.d

here F = applied force due to which work is done

d = displacement of object

now here we will have

W = 588 J

d = 1.4 m

now we can find force by above formula

588 = F* 1.4

F =\frac{588}{1.4}

F = 420 N

So applied force by milkman is F = 420 N

7 0
3 years ago
1. What is the gravitational force between two 4 kilogram masses separated by a distance of 5
Anon25 [30]
Yo, I assumed that this situation occurs on Earth otherwise the answer would be different.

7 0
3 years ago
A distracted driver is driving towards a turn where the edge of the road leads into a 75.0 m cliff. The velocity of the vehicle
Vlada [557]

As long as the car is on the road, it moves with a constant speed of 80km/h.

As soon as the car starts to fall down the cliff, it follows a parabolic motion. It means that it still moves with constant speed along the x axis, but it also starts to move along the y axis, with constant acceleration (i.e. the acceleration due to gravity).

The good thing about parabolic motions is that the two motions along the x and y axes are completely separable.

So, first of all, we need to know how long it takes for an object to fall for 75m. The equation of a constantly accelerated motion is

s=s_0+v_0t+\dfrac{1}{2}at^2

Where s_0 is the initial position, v_0 is the initial speed, and a is the constant rate of acceleration. In our case, we start from an initial height of 75m, an initial (vertical!) speed of zero, and our acceleration is -g. So, our equation becomes

s=75-\dfrac{g}{2}t^2

And we want to solve for the time when s=0 (i.e. we want to know how long will it take for the object to reach the ground). We have

0=75-\dfrac{g}{2}t^2 \iff 75=\dfrac{g}{2}t^2 \iff \dfrac{2\cdot75}{g}=t^2 \iff t=\sqrt{\dfrac{150}{g}}

(I'm discarding the negative solution because it wouldn't make sense)

Now that we've used the vertical motion to find out the falling time, we can go back to the horizontal motion. We know that the car moves for a certain amount of time at a certain speed. So, we simply have to plug our values in the s=vt equation, to get

s=80\sqrt\dfrac{150}{g}}

This is how far from the base of the cliff the vehicle lands.

3 0
3 years ago
Please I need help its timed-
leva [86]

Answer:

c

Explanation:

6 0
3 years ago
N capacitors are connected in parallel to form a "capacitor circuit". The capacitance of first capacitor is C, second one is C/2
liberstina [14]

Answer:

2C

Explanation:

The equivalent capacitance of a parallel combination of capacitors is the sum of their capacitance.

So, if the capacitance of each capacitor is half the previous one, we have a geometric series with first term = C and rate = 0.5.

Using the formula for the sum of the infinite terms of a geometric series, we have:

Sum = First term / (1 - rate)

Sum = C / (1 - 0.5)

Sum = C / 0.5 = 2C

So the equivalent capacitance of this parallel connection is 2C.

5 0
4 years ago
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