Question

Find the resultant vector (mag. and dir.) given the following information: Ax = 5.7, Ay = 3.4

Answer 1

Answer:

  Magnitude = 6.64

  Direction = $30.82^0$ from horizontal.

Explanation:

 We have horizontal component of vector Ax = 5.7 and vertical component of vector Ay = 3.4.

 Magnitude of vector acting perpendicularly = $\sqrt{A_x^2+A_y^2}$

 Substituting

    $A=\sqrt{A_x^2+A_y^2} =\sqrt{5.7^2+3.4^2} =6.64$

Direction θ = $tan^{-1}(\frac{A_y}{A_x} )$

  Substituting

      θ =$tan^{-1}(\frac{A_y}{A_x} )= tan^{-1}(\frac{3.4}{5.7})=30.82^0$