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Rina8888 [55]
3 years ago
15

Find the resultant vector (mag. and dir.) given the following information: Ax = 5.7, Ay = 3.4

Physics
1 answer:
Mashcka [7]3 years ago
7 0

<u>Answer:</u>

  Magnitude = 6.64

  Direction = 30.82^0 from horizontal.

<u>Explanation:</u>

 We have horizontal component of vector Ax = 5.7 and vertical component of vector Ay = 3.4.

 Magnitude of vector acting perpendicularly = \sqrt{A_x^2+A_y^2}

 Substituting

    A=\sqrt{A_x^2+A_y^2} =\sqrt{5.7^2+3.4^2} =6.64

Direction θ = tan^{-1}(\frac{A_y}{A_x} )

  Substituting

      θ =tan^{-1}(\frac{A_y}{A_x} )= tan^{-1}(\frac{3.4}{5.7})=30.82^0

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