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wolverine [178]

3 years ago

8

Which quantity is most closely related to the speed of gas particles?

2 answers:

just olya [345]3 years ago

5 0

Answer: Temperature

Explanation: According to Kinetic molecular Theory of gases temperature is directly proportional to the kinetic energy of the gas particle which leads to the speed of the gas.

Thus When the temperature increases, thermal motion of the particles increases which lead to the increase in the speed of the particle as they start moving in random directions.

They collide with each other and with the walls of the container during this process as well.

max2010maxim [7]3 years ago

3 0

The temperature of the gas, the hotter they get the faster they move. the colder they get, the slower they move

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True or false A compound can consist of one kind of element?

slavikrds [6]

False because a compound is one or more elements

6 0

3 years ago

Given that a chlorine-oxygen bond has an enthalpy of 243 kJ/mol , an oxygen-oxygen bond has an enthalpy of 498 kJ/mol , and the

Alecsey [184]

Explanation:

The chemical equation is as follows.

$\frac{1}{2}Cl_{2}(g) + \frac{1}{2}O_{2}(g) \rightarrow ClO(g)$

And, the given enthalpy is as follows.

$\frac{1}{2}Cl_{2}(g) + O_{2}(g) \rightarrow ClO_{2}(g)$ ; $\Delta H$ = 102.5 kJ

Cl-Cl = 243 kJ/mol, O=O = 498 kJ/mol

Since, the bond enthalpy of Cl-Cl is not given so at first, we will calculate the value of Cl-Cl as follows.

$\Delta H = \sum \text{bond broken in reactants} - \sum \text{bond broken in products}$

102.5 = $[(\frac{1}{2})x + 498] - [(2)(243)]$

102.5 = $(\frac{1}{2})x + 498 - 486$

102.5 - 12 = $\frac{x}{2}$

x = 181 kJ

Now, total bond enthalpy of per mole of ClO is calculated as follows.

$\Delta H = \sum E(\text{bond broken in reactants}) - \sum (\text{bond broken in products})$

x = $[(\frac{1}{2})181 + (\frac{1}{2})498] - 243$

= 339.5 - 243

= 96.5 kJ

Thus, we can conclude that the value for the enthalpy of formation per mole of ClO(g) is 96.5 kJ.

8 0

3 years ago

Place each statement in the column of the particle that it best describes.<br> Refer To Photo

MrRa [10]

The options are labelled as:

1 2

3 4

5 6

7 8

Protons: 1, 5, 7

Neutrons: 2, 8

Electron: 3, 4, 6

5 0

3 years ago

What are the classes of alkanol

LuckyWell [14K]

1-PRIMARY ALKANOL 2-SECONDARY ALKANOL 3-TERTIARY ALKANOL

8 0

3 years ago

The following information is to be used for the next 2 questions. In order to analyze for Mg and Ca, a 24-hour urine sample was

Ainat [17]

Answer:

Explanation:

From the given information:

The concentration of metal ions are:

$[Ca^{2+}]= \dfrac{0.003474 \ M \times 20.49 \ mL}{10.0 \ mL}$

$[Ca^{2+}]=0.007118 \ M$

$[Mg^2+] = \dfrac{0.003474 \ M\times (26.23 - 20.49 )mL}{10.0 \ mL}$

$=0.001994 \ M$

Mass of Ca²⁺ in 2.00 L urine sample is:

$= 2.00 L \times 0.001994 \dfrac{mol}{L} \times \dfrac{40.08 \ g}{1 \ mol}$

= 0.1598 g

Mass of Ca²⁺ = 159.0 mg

Mass of Mg²⁺ in 2.00 L urine sample is:

$= 2.00 L \times 0.007118 \dfrac{mol}{L} \times \dfrac{24.31 \ g}{1 \ mol}$

= 0.3461 g

Mass of Mg²⁺ = 346.1 mg

5 0

3 years ago