Answer:
457.5kPa
Explanation:
Given data
V1=V2=350mL (<em>fixed volume</em> )
P1=366kPa
T1= 88 degrees Celsius
P2=??
T2= 110 degrees Celsius
For the general gas equation
P1V1/T1= P2V2/T2
V1=V2
P1/T1= P2/T2
Substitute
366/88= P2/110
Cross multiply we have
P2*88=366*110
P2*88= 40260
P2= 40260/88
P2= 457.5 kPa
Hence the pressure will change to 457.5kPa
I guess it is A and i think i m correct
The grams of aluminium oxide are formed when 350 kj heat are released is calculated as follows
1mole = 850Kj
what about 350kj
=1mole x350/850 = 0.412 moles
mass of Al = moles of Al x molar mass of Al
= 0.412mol x 27 g/mol = 11.124 grams
