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3 years ago

Which of the following is NOT a postulate of the Kinetic Molecular Theory?

Chemistry

1 answer:

kotegsom [21]3 years ago

8 0

Answer:

"3. Energy can either be destroyed or created. Its goes from one form to another."

Explanation:

The third answer choice, "3. Energy can either be destroyed or created. Its goes from one form to another. " is related to the Law of Conservation of Energy from thermodynamics. Is it not a postulate of the Kinetic Molecular Theory.

"1. Average Kinetic Energy of the system is a measure of the temperature of the system."

Postulate of Kinetic Molecular Theory $\checkmark$

The average kinetic energy of the system is measured by its temperature and nothing else

"2. Energy is conserved in the collisions between gas molecules.."

Postulate of Kinetic Molecular Theory $\checkmark$

All collisions between gas molecules are perfectly elastic, meaning no energy is lost

"3. Energy can either be destroyed or created. Its goes from one form to another.

$\times$ NOT a Postulate of Kinetic Molecular Theory

Related to Conservation of Energy from thermodynamics

"4. Gases travel in straight line until they collide with other gas molecules"

Postulate of Kinetic Molecular Theory $\checkmark$

All gas molecules will travel in a straight line until they collide with other gas molecules or some object (e.g. a container)

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Misha Larkins [42]

Explanation:

Let the volume of the solution be 100 ml.

As the volume of glycol = 50 = volume of water

Hence, the number of moles of glycol = $\frac{mass}{molar mass}$

= $\frac{density \times volume}{molar mass}$

= $\frac{1.1088 \times 50}{62 g/mol}$

= 0.894 mol

Hence, number of moles of water = $\frac{50 \times 0.998}{18}$

= 2.77

As glycol is dissolved in water.

So, the molality = $0.894 \times \frac{1000}{49.92}$

= 17.9

Therefore, the expected freezing point = $-1.86 \times 17.9$

= $-33.31^{o}C$

Thus, we can conclude that the expected freezing point is $-33.31^{o}C$ .

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3 years ago

How many moles are in 50 g of CO2

murzikaleks [220]

Answer:

1.1 mol

Explanation:

n=m/M, where n is moles, m is mass, and M is molar mass.

M of CO2 = 12.01+16.00+16.00 = 44.01g/mol

n=50g/44.01g/mol

n = 1.13610543 mol

n ≈ 1.1 mol

Hope that helps

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2 years ago

A sample of argon gas at 55°C is under 845 mm Hg pressure. What will the new temperature be if the pressure is raised to 1050 mm

Maurinko [17]

Answer:

The final temperature at 1050 mmHg is 134.57 $^{\circ}C$ or 407.57 Kelvin.

Explanation:

Initial temperature = T = 55 $^{\circ}C$ = 328 K

Initial pressure = P = 845 mmHg

Assuming final to be temperature to be T' Kelvin

Final Pressure = P' = 1050 mmHg

The final temperature is obtained by following relation at constant volume

$\displaystyle \frac{P}{P'}=\displaystyle \frac{T}{T'} \\ \displaystyle \frac{845 \textrm{ mmHg}}{1050 \textrm{ mmHg}} = \displaystyle \frac{328 \textrm{ K}}{T'} \\T' = 407.57 \textrm{ Kelvin}$

The final temperature is 407.57 K

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3 years ago

Name the following compound: CH3-CH2-CH2-CH2-CH3 CH3 CH3

stepan [7]

Answer:

Pentane

Explanation:

since we have in here CH3-CH2-CH2-CH2-CH3 5 Carbon atoms and 12 Hydrogen making it $C_{5} H_{12}$

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3 years ago

Rank these compounds by their expected boiling point? CH4 CH3Cl CH3OH? Lowest to highest; 10+ for the best explanation. Thank yo

docker41 [41]

Methane, CH4, would have the lowest boiling point among the three since it has the lowest number of carbon and has no functional groups. Methanol would have the highest boiling point since it has a functional group which contains hydrogen bonding which much stronger than the one in CH3Cl. Hope this helps.

3 0

3 years ago

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