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ANTONII [103]
3 years ago
7

If I add water to 100Ml of a 0.75 m NaOH solution until the final volume is 165 ml , what will the molarity of the diluted solut

ion be?
Chemistry
1 answer:
Mamont248 [21]3 years ago
8 0

Answer:

0.45M

Explanation:

The following were obtained from the question:

C1 = 0.75M

V1 = 100mL

V2 = 165mL

C2 =?

Applying the dilution formula C1V1 = C2V2, the concentration of the diluted solution can be calculated for as follows:

0.75 x 100 = C2 x 165

Divide both side by 165

C2 = (0.75 x 100) /165

C2 = 0.45M

The concentration of the diluted solution is 0.45M

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JulijaS [17]

Answer:

It is 20. g HF

Explanation:

H2 + F2 ==> 2HF  ...  balanced equation

Since the question is asking us to find the mass of product formed, we will want to first convert the molecules of H2 into moles of H2 (we could do this at the end of the calculations, but it's just as easy to do it now).

moles of H2 present (using Avogadro's number):  

3.0x1023 molecules H2 x 1 mole H2/6.02x1023 molecules = 0.498 moles H2

From the balanced equation, we see that 1 mole H2 produces 2 moles HF.  Therefore, we can now find the theoretical mass of HF produced from 0.498 moles H2:

0.498 moles H2 x 2 moles HF/1 mol H2 = 0.996 moles HF formed.

The molar mass of HF = 20.01 g/mole, thus...

0.996 moles HF x 20.01 g/mole = 19.93 g HF = 20. g HF formed (to 2 significant figures)

6 0
2 years ago
Consider the unbalanced equation for the oxidation of aluminum.
SashulF [63]
In order to balance an equation, we apply the principle of conservation of mass, which states that mass can neither be created nor destroyed. Therefore, the mass of an element before and after a reaction remains constant. Here, the balanced equation becomes:
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The coefficients are 4, 3 and 2.
8 0
3 years ago
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Your dad is working on creating a brick border for the lake in your backyard each brick has a mass of 100 g and a volume of 20 c
wel

Answer:

5000kg/m³

Explanation:

density=mass/volume

d=m/v

d=100/20

=5g/cm³

g/cm³*1000=kg/m³

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Answer:

Your question is complex, because I think you wrote it wrong.

Although in front of this what I can help you is that the carbons are associated between a single, double or triple union.

This depends on whether they are attached to more or less carbons or hydrogens, the carbons have the possibility of joining 4 radicals, both other carbons and hydrogens.

Simple junctions talks about compound organisms called ALKANS.

The double unions, in organic these compounds are called as ALQUENOS.

And as for the tertiary unions, the organic chemistry names them as ALQUINOS.

These compounds that we write, a simple union, the less energy, the less this union, that is why the triple bond is the one that contains the most energy when breaking or destroying it in a reaction.

Explanation:

In a chemical compound the change of these unions if we modified them we would generate changes even in the classifications naming them as well as different compounds and not only that until they change their properties

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