Question

Find the magnitude of the electrostatic force between a Na+ ion and a Cl− ion separated by 0.46 nm. N (b) Would the answer change if the sodium ion were replaced by Li+ and the chloride ion by Br−?

Answer 1

Answer:

electrostatic force = 1.08 ×$10^{-9}$  N

and if sodium ion replace by Li+ and chloride by Br− then there will be no change in electrostatic force

magnitude of electrostatic force will be same

Explanation:

given data

separation d = 0.46 nm = 4.6 ×$10^{-10}$ m

to find out

electrostatic force between Na+ and Cl− ion

and if sodium ion replace by Li+ and chloride by Br−

solution

we know electrostatic force formula that is

electrostatic force = K ×Q1×Q2 / d²          .........................1

here k is coulombs constant that is = 9 ×$10^{9}$ and Q1 and Q2 is

charge that is Q1 = + 1.6 ×$10^{-19}$ C

and Q2 = - 1.6 ×$10^{-19}$  C

so put all these value in equation 1

electrostatic force = K ×Q1×Q2 / d²

electrostatic force =  9 ×$10^{9}$  ×1.6 ×$10^{-19}$ × -1.6 ×$10^{-19}$ / (4.6 ×$10^{-10}$)²

so electrostatic force = 1.08 ×$10^{-9}$  N

and if sodium ion replace by Li+ and chloride by Br− then there will be no change in electrostatic force

so magnitude of  electrostatic force will be same