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DerKrebs [107]
3 years ago
14

The electric potential at the surface of a charged conductor _______.

Physics
1 answer:
frez [133]3 years ago
6 0

Answer:

The electric potential at the surface of a charged conductor<u> is always such that the potential is zero at all points inside the conductor.</u>

Explanation:

Each point on the surface of a balanced charged conductor has the same electrical potential.

The surface on any charged conductor in electrostatic equilibrium is an equipotential surface. Since the electric field is equal to zero inside the conductor, the electric potential at any point inside and on the surface is equivalent to its value.

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A parachutist of mass 56.0 kg jumps out of a balloon at a height of 1400 m and lands on the ground with a speed of 5.10 m/s. How
Vlad [161]

Answer:

769,048.28Joules

Explanation:

A parachutist of mass 56.0 kg jumps out of a balloon at a height of 1400 m and lands on the ground with a speed of 5.10 m/s. How much energy was lost to air friction during this bump

The energy lost due to friction is expressed using the formula;

Energy lost  = Potential Energy + Kinetic Energy

Energy lost  = mgh + 1/2mv²

m is the mass

g is the acceleration due to gravity

h is the height

v is the speed

Substitute the given values into the formula;

Energy lost  = 56(9.8)(1400) + 1/2(56)(5.10)²

Energy lost  = 768,320 + 728.28

Energy lost  = 769,048.28Joules

<em>Hence the amount of energy that was lost to air friction during this jump is 769,048.28Joules</em>

6 0
2 years ago
You want to determine your speed running across the room. what is one piece of data you need
Reika [66]
The distance you run divided by how long it takes

hope this is what you waned :)
3 0
3 years ago
A jogger runs the first 1000 meters of a race in 250 seconds. What is the joggers speed
Andrei [34K]
4 meters per second. hope this helped
7 0
3 years ago
Read 2 more answers
What is a group on the periodic table?
ehidna [41]

Answer:

A group is a column (vertical, up and down)

Explanation:

A group is vertical and a period is horizontal!

Hope i helped you

Have a great day!

4 0
2 years ago
Read 2 more answers
A 45 g bug is hovering in the air. A gust of wind
MariettaO [177]

The work-done by the wind as the bug undergoes the displacement is 80 J.

The given parameters;

  • Mass of the bug, m = 45 g
  • Force exerted, F = (4.0 î – 6.0j) x 10⁻² N
  • Displacement of the bug, r = (8.0î - 8.0j) m

The work-done by the wind as the bug undergoes the displacement is obtained by finding the dot product of the force and the displacement;

Work done = F. r

Work done = (4.0 î – 6.0j) x 10⁻² . (8.0î - 8.0j)

Work done = (32i²) + (48j²)

Work done = 32(1) + 48(1)

Work done = 80 J.

Thus, the work-done by the wind as the bug undergoes the displacement is 80 J.

Learn more here:brainly.com/question/19498865

5 0
2 years ago
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