Answer:
Bundling up, starting a fire, body warmth, blankets, taking a hot shower/bath.
Answer:
0.23 g
Explanation:
From the question given above, the following data were obtained:
Mass of solution = 20.3 g
Percentage by mass of KCl = 1.14%
Mass of KCl =?
The mass of KCl in the solution can be obtained as follow:
Percentage by mass = mass of solute / mass of solution × 100
1.14% = mass of KCl / 20.3
Cross multiply
Mass of KCl = 1.14% × 20.3
Mass of KCl = 1.14/100 × 20.3
Mass of KCl = 0.0114 × 20.3
Mass of KCl = 0.23 g
Therefore, the mass of KCl in the solution is 0.23 g
The statement which correctly describe the relationship between the reactants and the yield is this: 'the theoretical yield is calculated from the amount of the limiting reactants present'. The theoretical yields is the ideal maximum amount of a product that can be produced during a chemical reaction while the limiting reactant is the reactant that determines the maximum amount of product that can be formed.
Answer:
0.055g/mL
Explanation:
Data obtained from the question include:
Molar Mass of the gass sample = 71g/mol
Volume of the gas sample = 1300 mL
Density =?
The density of a substance is simply mass per unit volume. It is represented mathematically as:
Density = Mass /volume.
With the above equation, we can easily obtain the density of sample of gas as illustrated below:
Density = 71g / 1300 mL
Density = 0.055g/mL
Therefore, the density of the gas sample is 0.055g/mL
Answer : The equilibrium constant 
for the reaction is, 0.869
Explanation :
First we have to calculate the concentration of 
.
The balanced equilibrium reaction is,
Initial conc. C 0
At eqm. conc. 
As we are given,
The percent of dissociation = 
= 37 % = 0.37
Now we have to calculate the equilibrium constant for the reaction.
The expression of equilibrium constant for the reaction will be :
![K_c=\frac{[NO_2]^2}{[N_2O_4]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BNO_2%5D%5E2%7D%7B%5BN_2O_4%5D%7D)
Now put all the values in this expression, we get :
Therefore, the equilibrium constant for the reaction is, 0.869
