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telo118 [61]
3 years ago
15

Because of water erosion a sandy coast can erode about five meters every five years. Suppose the coast continue to erode at the

same rate. How much will the coast erode in fifty years
Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
8 0
It would erode 50 meters
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State the x value of the x intercept describe by the following <br> linear equation: (-3x-2y = 9
aivan3 [116]

Answer:

x=-3

Step-by-step explanation:

-3x-2y=9

-3x-2(0)=9

-3x-0=9

-3x=9

x=-3

3 0
3 years ago
• karger's min cut algorithm in the class has probability at least 2/n2 of returning a min-cut. how many times do you have to re
MrRissso [65]
The Karger's algorithm relates to graph theory where G=(V,E)  is an undirected graph with |E| edges and |V| vertices.  The objective is to find the minimum number of cuts in edges in order to separate G into two disjoint graphs.  The algorithm is randomized and will, in some cases, give the minimum number of cuts.  The more number of trials, the higher probability that the minimum number of cuts will be obtained.

The Karger's algorithm will succeed in finding the minimum cut if every edge contraction does not involve any of the edge set C of the minimum cut.

The probability of success, i.e. obtaining the minimum cut, can be shown to be ≥ 2/(n(n-1))=1/C(n,2),  which roughly equals 2/n^2 given in the question.Given: EACH randomized trial using the Karger's algorithm has a success rate of P(success,1) ≥ 2/n^2.

This means that the probability of failure is P(F,1) ≤ (1-2/n^2) for each single trial.

We need to estimate the number of trials, t, such that the probability that all t trials fail is less than 1/n.

Using the multiplication rule in probability theory, this can be expressed as
P(F,t)= (1-2/n^2)^t < 1/n 

We will use a tool derived from calculus that 
Lim (1-1/x)^x as x->infinity = 1/e, and
(1-1/x)^x < 1/e   for x finite.  

Setting t=(1/2)n^2 trials, we have
P(F,n^2) = (1-2/n^2)^((1/2)n^2) < 1/e

Finally, if we set t=(1/2)n^2*log(n), [log(n) is log_e(n)]

P(F,(1/2)n^2*log(n))
= (P(F,(1/2)n^2))^log(n) 
< (1/e)^log(n)
= 1/(e^log(n))
= 1/n

Therefore, the minimum number of trials, t, such that P(F,t)< 1/n is t=(1/2)(n^2)*log(n)    [note: log(n) is natural log]
4 0
3 years ago
Three is added to a number, and the sum is multiplied by 4. The result is 16.
zubka84 [21]

Answer:

I think one.

Step-by-step explanation:

Because 16 divided by 4 is 4 minus the 3 and its 1. So I think 1 is the mystery number.

hope i help

8 0
3 years ago
Read 2 more answers
The total travel time for the ranger to get to the car is the sum of the travel time in the forest and the travel time on the ro
Yuki888 [10]

Answer:

[ext]T(x) = 2C / Speed[/ext]

Step-by-step explanation:

[ext]Time taken for the Ranger to get to the car = Sum total time taken to travel in the forest and on the road[/ext]

Since [ext]distance of the Ranger to the car = C[/ext]

[ext]Time taken = distance/speed[/ext]

[ext]Total Time taken T(x) = 2 * C / speed[/ext]

T(x) = 2C / speed

4 0
3 years ago
The slope of a line is 1, and the y-intercept is -1. What is the equation of the line written in slope-intercept form?
Monica [59]

Answer:

The answer is y= x -1.

Step-by-step explanation:

here, given that; the slope is 1 and y intercept is 1. so, the formula of equation of a st. line in slope intercept form is y= mx+ c.

so, y= 1×x-1 (putting value of slope as one and y intercept as -1).

therefore, the answer is y= x-1....answer.

<em><u>hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

5 0
3 years ago
Read 2 more answers
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