You apply a 50 N rightward force to a 4 kg cart to accelerate it across a horizontal surface at a rate of 3.28m/s2.
1 answer:
Answer:
The force of friction is 36.88 N
The coefficient of friction is 0.94
Explanation:
Lets explain how to solve the problem
The force applied is 50 N rightward
The mass of the cart is 4 kg
The applied force makes the cart accelerate across a horizontal surface
The acceleration is 3.28 m/s²
We need to find the force of friction acting upon the cart
According to Newton's law
→ ∑ F in direction of motion = mass × acceleration
We have two horizontal forces acting on the cart
→ The force applied = 50 N
→ The force of friction in opposite direction of motion
→ The mass = 4 kg
→ Acceleration = 3.28 m/s²
Substitute these values in the rule
→ 50 - = 4 × 3.28
→ 50 - = 13.12
Add for both sides
→ 50 = + 13.12
Subtract 13.12 from both sides
→ 36.88 =
<em>The force of friction is 36.88 N</em>
→ The force of friction = μ R
where R is the normal reaction and μ is the coefficient of friction
→ R = mg
where m is the mass of the cart and g is the acceleration of gravity
→ = μ mg
→ g = 9.8 m/s² , m = 4 kg , = 36.88 N
Substitute these values in the rule
→ 36.88 = μ (4)(9.8)
→ 36.88 = 39.2 μ
Divide both sides by 39.2
→ μ = 0.94
<em>The coefficient of friction is 0.94</em>
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Answer:
Explanation:
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-14.5 = -9.8t so
t = 1.5 seconds