X = 15 , see photo for solutions
Answer:
(y^2+3y-28)/(4y^2-15y-4)
Step-by-step explanation:
(4y-1)(y-3)(2y+3)(y+3)(y+7)(y-3)/(2y+3)(y-4)(4y+1)(4y-1)(y-3)(y+3)
= (y+7)(y-3)/(y-4)(4y+1)
= (y^2+3y-28)/(4y^2-15y-4)
Answer:
X1=(-3+7)÷2=2---> X1=2-->First root
X2=(-3-7)÷2=-5---> X2= -5-->Second root
Step-by-step explanation:
X^2=-3X+10 you need to change the order of this equation
X^2+3X-10=0---> You do this in order to do BHASKARA
then you do BHASKARA
-3(±√9-4·1·-10)÷2·1
X1=(-3+7)÷2=2---> X1=2-->First root
X2=(-3-7)÷2=-5---> X2= -5-->Second root
10 cm would stay as a 10 cm
14cm would round down to a 10