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Sever21 [200]
4 years ago
7

When θ= 0 ̊, the assembly is held at rest, and the torsional spring is untwisted. if the assembly is released and falls downward

, determine its angular velocity at the instant θ= 90 ̊. rod ab has a mass of 6 kg, and the disk c has a mass of 9 kg. note: the moment due to a torsional spring is, m = kθ; where k is the stiffness of the spring?
Physics
1 answer:
Georgia [21]4 years ago
7 0
Rod is 450mm and disk has a radius of 75mm So there is a pin holding the assembly upwards which is when Θ=0 and at the pin there is a torsional spring with constant of k=20N m/rad. One end of the rod is attached to the pin and the other is attached to the disk.


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(B) V_f=0.3358\ m

Explanation:

Given:

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P_i=\frac{m_p.g}{\pi.d^2\div 4}

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Given:

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V_i=\pi.d.h_i

V_i=\pi\times 0.24\times 0.9

V_i=0.6786\ m^3

Using gas law:

\frac{P_i V_i}{T_i}= \frac{P_f V_f}{T_f} ........................................(1)

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∴P_i=P_f

<u>Hence eq. (1) is reduced to:</u>

\frac{V_i}{T_i}= \frac{V_f}{T_f}

putting respective values:

\frac{0.6786}{588}= \frac{V_f}{291}

V_f=0.3358\ m

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