Complete Question
A flat loop of wire consisting of a single turn of cross-sectional area 8.00 cm2 is perpendicular to a magnetic field that increases uniformly in magnitude from 0.500 T to 1.60 T in 0.99 s. What is the resulting induced current if the loop has a resistance of 
Answer:
The current is 
Explanation:
From the question we are told that
The area is 
The initial magnetic field at 
is 
The magnetic field at 
is 
The resistance is 
Generally the induced emf is mathematically represented as
=> 
=> 
Generally the current induced is mathematically represented as
=> 
=>
The speed of sound at T=25°C is Vs=346 m/s. So the sound has to reach the cliff and return back to you so the path it needs to travel is s=2*440 m = 880 m.
Since the speed of sound is constant s=Vs*t, and t= s/Vs=880/346=2.54335 s. You will hear the echo after t=2.54335 s after you shouted.
<span>2.5 m/s going upward.
In the situation described, Erica and Danny undergo a non-elastic collision which will conserve their combined momentum. Since Erica is stationary, her momentum is 0. And since Danny is moving upward at 4.7 m/s his momentum is 43 kg * 4.7 m/s = 202.1 kg*m/s. Assuming that both Erica and Danny will be moving as a joined system, their combined mass is 38 kg + 43 kg = 81 kg. Since the momentum will be the same, their velocity will be 202.1 kg*m/s / 81 kg = 2.495061728 m/s. Since we only have 2 significant figures in the provided data, rounding the result to 2 significant figures gives a velocity of 2.5 m/s going upward.</span>
Answer:
F = 2.69 10⁻³ m [ N]
Explanation:
This exercise asks to calculate the gravitational field of the Earth on the lunar surface, let's use the universal gravitation law
F = G m M / r²
where m is the mass of the body, M the mass of the Earth and r the distance between the Earth and the Moon
F = (G M / r²) m
F = (6.67 10⁻¹¹ 5.98 10²⁴ / (3.85 10⁸)² ) m
F = 2.69 10⁻³ m [ N]
This force is directed from the Moon towards the Earth, therefore it reduces the weight of the body
