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labwork [276]
3 years ago
10

The planet Jupiter’s mean orbital radius is 5.2025 AU’s. what is the period of Jupiter in earth years?

Physics
1 answer:
Gre4nikov [31]3 years ago
7 0

11.86 years, or around that time it would take about 12 years.

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A 1.2 x10 3 kilogram automobile in motion strikes a 1.0 x 10 -4 kilogram insect as a result the insect is accelerated at a rate
Mariana [72]
According to Newton's second law, the force applied to an object is equal to the product between the mass of the object and its acceleration:
F=ma
where F is the magnitude of the force, m is the mass of the object and a its acceleration.

In this problem, the object is the insect, with mass m=1.0 \cdot 10^{-4} kg. The acceleration of the insect is a=1.0 \cdot 10^2 m/s^2, therefore we can calculate the force exerted by the car on the insect:
F=ma=(1.0 \cdot 10^{-4} kg)(1.0 \cdot 10^2 m/s^2)=0.01 N

How do we find the force exerted by the insect on the car?
According to Newton's third law (known as action-reaction law), when an object A exerts a force on an object B, object B also exerts a force equal and opposite on object A. Therefore, the force exerted by the insect on the car is equal to the force exerted by the car on the object, so it is 0.01 N.
6 0
3 years ago
Find the acceleration produced.
krok68 [10]

Answer:

0.67m/s²

Explanation:

Given parameters:

Mass of toy  = 1.2kg

Force applied = 0.8N

Unknown:

Acceleration   = ?

Solution:

According to newton's second law of motion;

      Force  = mass x acceleration

Now,

      Acceleration = \frac{Force}{mass}

     Acceleration  = \frac{0.8}{1.2}   = 0.67m/s²

4 0
3 years ago
Read 2 more answers
You know what movie is rly good the great gastby and also ford v Ferrari
jolli1 [7]

Answer:HETJHETHRTHR

Explanation:

6 0
3 years ago
Water is diffrent from other substances because:
sergeinik [125]
Its B.hope this helps

8 0
3 years ago
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a skier is gliding along 3.0 m/s on horizontal, frictionless snow. he suddenly starts down a 10 degrees incline. his speed at th
Elza [17]
... find length
(way 1) determine acceleration using force
only force act on skier is mg vertically. spilt vector we get force along the incline = mgsin(10) and f= ma so
ma = mgsin(10) or a = gsin(10)
a (along the incline)= gsin(10) = 10sin(10) = 1.74
v^2 = u^2 + 2as
15^2 = 3^2 + 2(1.74)s
s = 62.06 m

(way 2) using conservation of energy
energy (KE+PE) on top = energy at bottom
0.5m3^2 + mgh = 0.5m15^2 +0
h (height of incline) = (112.5 - 4.5)/10 = 19.8 m
length of incline = h/sin(10) = 62.2 m ; trigonometry

... find time
s = (u+v)t/2
t = 2s/(u+v) = 2(62.2)/(3+15) = 6.91 s
4 0
3 years ago
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