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2 years ago

The planet Jupiter’s mean orbital radius is 5.2025 AU’s. what is the period of Jupiter in earth years?

Physics

1 answer:

Gre4nikov [31]2 years ago

7 0

11.86 years, or around that time it would take about 12 years.

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Which of the following statements is true about tides? (2 points)

andre [41]

1: Tides are caused by the location of the Earth, sun, and moon.

2: Tides occur about an hour later each day.
This is because of the earth's orbit and the moons position as they move.

3: Half as much as the moon
The moon affects the tide much more than the sun, as the moon is drastically closer to the earth than the sun.

4 0

3 years ago

The diagram shows a position-time graph What is the displacement of the object

algol13

The object is moving, so at different times, it has different displacement. I'm guessing that you probably want to know the displacement at the end of the time on the graph ... 5 seconds.

Displacement is the distance and the direction FROM (the position at the beginning) TO (the position at the end).

At the beginning ... time=0 ... the position is 1 meter.

At the end ... time=5 ... the position is zero.

The distance FROM the beginning TO the end is (zero - 1m) . That's -1m .

5 0

2 years ago

What is phyical quantity

puteri [66]

Answer:

physical quantity

Explanation:

All quantity in term of which laws of physics are described and can be measured is called physical quantity

8 0

3 years ago

Heat is the transfer of thermal energy from one object to another because of a difference in

evablogger [386]

The Answer Is Temprature. Hope This Helps :)

8 0

3 years ago

Read 2 more answers

Two equally charged insulating balls each weigh 0.16 g and hang from a common point by identical threads 35 cm long. The balls r

Dafna11 [192]

Answer:

Q₁ = Q₂ = 8.84 x 10⁻⁹ C

Explanation:

given,

mass of ball, m = 0.16 g = 1.6 x 10⁻⁴ Kg

ball each other, r = 6.8 cm

Weight of the ball

F_w = m g

F_w = 1.6 x 10⁻⁴ x 9.8

F_w = 1.56 x 10⁻³ N

The tension in each string is a force directed along the length of the string and is the hypotenuse of a right triangle.

we have to find the horizontal component of the forces.

The length of the string,L is 35 cm so, it will be the hypotenuse.

θ be the angle made with imaginary vertical line and the string.

now,

$sin \theta = \dfrac{r\2}{L}$

$sin \theta = \dfrac{3.4}{35}$

θ = 5.57°

horizontal component of the force = ?

vertical component of force,F_v = 1.56 x 10⁻³ N

$tan\theta = \dfrac{F_H}{F_v}$

$tan(5.57^0) = \dfrac{F_H}{1.56\times 10^{-3}}$

F_h = 1.52 x 10⁻⁴ N

now, each ball will be repelled by

F = 1.52 x 10⁻⁴ N

now calculation of charges

$F = \dfrac{kQ_1Q_2}{r^2}$

Q₁ = Q₂ because both charge are same

$1.52\times 10^{-4} = \dfrac{9\times10^9Q^2}{0.068^2}$

Q² = 7.809 x 10⁻¹⁷

Q = 8.84 x 10⁻⁹ C

hence the change on the balls were Q₁ = Q₂ = 8.84 x 10⁻⁹ C

5 0

3 years ago