I believe it’s 98.07848 g mol
Carbonic acid ---> water + carbon dioxide
so it's the second option
Answer:
Option A
Explanation:
The element X belongs to
=> Period 3 (Because it's valence shell is 3)
=> Group VI (Because electrons in the valence shell , 2+4 = 6)
Answer:
103.2 g of AgCl can be made in the reaction
Explanation:
We state the reaction to analyse the problem:
AlCl₃ + 3AgNO₃ → 3AgCl + Al(NO₃)₃
We convert the mass of chloride to moles:
32 g . 1mol/ 133.34g = 0.240 moles
Ratio is 1:3. See the stoichiometry
1 mol of aluminum chloride can produce 3 moles of AgCl
Then, 0.240 will produce (0.240 . 3)/1= 0.720 moles.
We convert the moles to mass: 0.720 mol . 143.32g/1mol = 103.2 g
Answer:
[H⁺] = 0.00013 M
[OH⁻] = 7.7 × 10⁻¹¹ M
Explanation:
Step 1: Calculate the concentration of H⁺ ions
HCl is a strong acid that dissociates according to the following equation.
HCl ⇒ H⁺ + Cl⁻
The molar ratio of HCl to H⁺ is 1:1. The concentration of H⁺ is 1/1 × 0.00013 M = 0.00013 M.
Step 2: Calculate the concentration of OH⁻ ions
We will use the ionic product of water equation.
Kw = 10⁻¹⁴ = [H⁺] × [OH⁻]
[OH⁻] = 10⁻¹⁴/[H⁺] = 10⁻¹⁴/0.00013 = 7.7 × 10⁻¹¹ M
