What is the name of Fe2(so4)3

Mr. Ragusa asks Hassan to make silver crystals from the following reaction.

SVEN [57.7K]

Answer:

Percentage yield = 61.7%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated:

2AgNO₃ + Cu —> Cu(NO₃)₂ + 2Ag

Next, we shall determine the mass of AgNO₃ that reacted and the mass of Ag produced from the balanced equation. This is illustrated below:

Molar mass of AgNO₃ = 108 + 14 + (16×3)

= 108 + 14 + 48

= 170 g/mol

Mass of AgNO₃ from the balanced equation = 2 × 170 = 340 g

Molar mass of Ag = 108 g/mol

Mass of Ag from the balanced equation = 2 × 108 = 216 g

SUMMARY:

From the balanced equation above,

340 g of AgNO₃ reacted to produce 216 g of Ag.

Next, we shall determine the theoretical yield of Ag. This can be obtained as follow:

From the balanced equation above,

340 g of AgNO₃ reacted to produce 216 g of Ag.

Therefore, 51 g of AgNO₃ will react to produce = (51 × 216)/340 = 32.4 g of Ag.

Thus, the theoretical yield of Ag is 32.4 g.

Finally, we shall determine the percentage yield of Ag. This can be obtained as follow:

Actual yield = 20 g

Theoretical yield = 32.4 g

Percentage yield =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield = 20 / 32.4 × 100

Percentage yield = 61.7%

6 0

3 years ago

The pressure that is the difference between the net hydrostatic pressure and the net colloid osmotic pressure is called

mina [271]

The pressure calculated as the difference between the net hydrostatic pressure and the net colloid osmotic pressure is known as: filtration pressure.

<h3>What is pressure?</h3>

Pressure can be defined as a measure of the force exerted per unit area of an object or body. Thus, it is usually measured in Newton per meter square.

<h3>The types of pressure.</h3>

In Science, there are different types of pressure and these include the following:

Hydrostatic pressure

Atmospheric pressure

Osmotic pressure

Filtration pressure

Filtration pressure is a pressure that is typically calculated as the difference between the net hydrostatic pressure and the net colloid osmotic pressure. Also, it promotes the filtration of fluid through a membrane.

Read more on pressure here: brainly.com/question/24827501

4 0

3 years ago

How much heat is needed to raise the temperature of 55.0 g sample of water by 65.0 oC.

sveticcg [70]

Answer: 14943.5 J

Explanation:

The quantity of heat energy (Q) required to raise the temperature of a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)

Thus, Q = MCΦ

Given that,

Q = ?

Mass of water = 55.0g

C = 4.18 J/g°C

Φ = 65.0°C

Then, Q = MCΦ

Q = 55.0g x 4.18 J/g°C x 65.0°C

Q = 14943.5 J

Thus, 14943.5 joules of heat is needed to raise the temperature of water.

3 0

3 years ago

Read 2 more answers

What is the formula for sulfur hexa fluoride?

vlabodo [156]

S2F6, is the correct answer I believe!

6 0

3 years ago

Read 2 more answers

Consider the reaction given below.

Drupady [299]

Answer:

<u>K = 0.167 s⁻¹</u>

Explanation:

<u>1) Rate law, at a given temperature:</u>

Since all the data are obtained at the same temperature, the equilibrium constant is the same.

Since only reactants A and B participate in the reaction, you assume that the form of the rate law is:

r = K [A]ᵃ [B]ᵇ

<u>2) Use the data from the table</u>

Since the first and second set of data have the same concentration of the reactant A, you can use them to find the exponent b:

r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

r₂ = (1.50)ᵃ (2.50)ᵇ = 2.50 × 10⁻¹ M/s

Divide r₂ by r₁: [ 2.50 / 1.50] ᵇ = 1 ⇒ b = 0

Use the first and second set of data to find the exponent a:

r₁ = (1.50)ᵃ (1.50)ᵇ = 2.50 × 10⁻¹ M/s

r₃ = (3.00)ᵃ (1.50)ᵇ = 5.00 × 10⁻¹ M/s

Divide r₃ by r₂: [3.00 / 1.50]ᵃ = [5.00 / 2.50]

2ᵃ = 2 ⇒ a = 1

<u>3) Write the rate law</u>

r = K [A]¹ [B]⁰ = K[A]

This means, that the rate is independent of reactant B and is of first order respect reactant A.

With the first set of data

r = K (1.50 M) = 2.50 × 10⁻¹ M/s ⇒ K = 0.250 M/s / 1.50 M = 0.167 s⁻¹

Result: the rate constant is K = 0.167 s⁻¹

6 0

4 years ago