First find the mass
44.1 ml @ 1.55 g/mL = 68.355 grams of Ca
the equation
Ca + O2 → CaO
= 55 grams of O2
Ok so O3 has a greater electronegativity and is taken into account first, -2*3=-6, so As has to equal 6/2=3, so As has a +3 oxidation number here
Answer:
22 electrons are in the compound CO2. And the correct answer is Phosphorus tribromide.
Explanation:
Answer:
D. Kb = 1.8 × 10⁻⁵
Explanation:
The strongest base has the largest Kb value.
The largest Kb value has the smallest negative exponent.
So, the strongest base has Kb = 1.8 × 10⁻⁵.
How many oxygen molecules are in 22.4 liters of oxygen gas
at 273k and 101.3kpa
First solve the number of moles of the oxygen gas by using
the ideal gas equation:
PV = nRT
Where n is the number of moles
n = PV/RT
n = (101 300 Pa) (22.4 L) (1 m3/1000 L ) / ( 8.314 Pa m3 /
mol K) ( 273 K)
n = 1 mol O2
the number of molecules can be solve using avogrados number
6.022x10^23 molecule / mole
molecules of one mole O2 = 6.022x 10^23 molecules
