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GenaCL600 [577]
3 years ago
7

Which of the following is the definition of an adaptation?

Chemistry
1 answer:
Serggg [28]3 years ago
6 0

Answer:

A

Explanation:

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Suppose that 100 grams of water at 50.0°C is placed in contact with 200 grams of iron at 30.0°C. The final
wel

Answer:

The answer would be 1.5 kJ.

Explanation:

When you use the equation q = m x c x ∆T you will be able to find the energy gained or lost. The data for the water in this case is just there to distract you so ignore it. :D

4 0
2 years ago
According to Bohr atomic model
nata0808 [166]

Answer:

A small positively charged nucleus surrounded by revolving negatively charged electrons in fixed orbits

7 0
3 years ago
What are the two ways ocean acidification affects marine life?
spayn [35]

Answer:

1) harm life forms that rely on carbonate-based shells and skeletons, 2) harm organisms sensitive to acidity

Explanation:

7 0
2 years ago
Read 2 more answers
What are the pH of these solutions?
Tju [1.3M]

Answer:

The answer to your question is below

Explanation:

a)    HCl  0.01 M

      pH = -log [0.01]

      pH = - (-2)

     pH = 2

b)    HCl = 0.001 M

      pH = -log[0.001]

      pH = -(-3)

      pH = 3

c)    HCl = 0.00001 M

       pH = -log[0.00001]

       pH = - (-5)

      pH = 5

d) Distilled water

      pH = 7.0

e) NaOH = 0.00001 M

       pOH = -log [0.00001]

       pOH = -(-5)

       pH = 14 - 5

       pH = 9

f)  NaOH = 0.001 M

      pOH =- log [0.001]

      pOH = 3

      pH = 14 - 3

      pH = 11

g)   NaOH = 0.1 M

       pOH = -log[0.1]

       pOH = 1

       pH = 14 - 1

       pH = 13

3 0
3 years ago
A 7.27-gram sample of a compound is dissolved in 250. grams of benzene. The freezing point of this solution is 1.02°C below that
UkoKoshka [18]

Answer:

The correct answer is 146 g/mol

Explanation:

<em>Freezing point depression</em> is a colligative property related to the number of particles of solute dissolved in a solvent. It is given by:

ΔTf = Kf x m

Where ΔTf is the freezing point depression (in ºC), Kf is a constant for the solvent and m is the molality of solution. From the problem, we know the following data:

ΔTf = 1.02ºC

Kf = 5.12ºC/m

From this, we can calculate the molality:

m = ΔTf/Kf = 1.02ºC/(5.12ºC/m)= 0.199 m

The molality of a solution is defined as the moles of solute per kg of solvent. Thus, we can multiply the molality by the mass of solvent in kg (250 g= 0.25 kg) to obtain the moles of solute:

0.199 mol/kg benzene x 0.25 kg = 0.0498 moles solute

There are 0.0498 moles of solute dissolved in the solution. To calculate the molar mass of the solute, we divide the mass (7.27 g) into the moles:

molar mass = mass/mol = 7.27 g/(0.0498 mol) = 145.9 g/mol ≅ 146 g/mol

<em>Therefore, the molar mass of the compound is 146 g/mol </em>

6 0
3 years ago
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