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finlep [7]
2 years ago
8

Is space-time and concept of "now" an illusion?

Physics
2 answers:
DedPeter [7]2 years ago
8 0
My opinion:. No. If it were an illusion, then different people might perceive it in different ways, but all normal people actuallt perceive it the same.
Orlov [11]2 years ago
6 0
May be

May be not


It is depend up on your level of thinkin



But in graduation may be not second option will consider



....
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The table below shows the acceleration of gravity on different bodies in the
Aloiza [94]

Answer:

Pluto

because the the gravitation strength is small, so it will be accelerating slow

8 0
2 years ago
Read 2 more answers
Type the correct answer in the box. use numerals instead of words. anne has a sample of a substance. its volume is 20 cm3, and i
CaHeK987 [17]

The density of sample is 5 g/cm3

Given:

volume of sample = 20 cm3

mass of sample = 100 grams

To Find:

density of sample

Solution: Density is the measure of how much “stuff” is in a given amount of space. For example, a block of the heavier element lead (Pb) will be denser than the softer, lighter element gold (Au). A block of Styrofoam is less dense than a brick. It is defined as mass per unit volume

density = mass/volume

d = 100/20

d = 5 g/cm3

So, density of sample is 5 g/cm3

Learn more about Density here:

brainly.com/question/1354972

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6 0
1 year ago
A cheetah can accelerate from rest at the rate of 4m /s
lesya [120]
Acceleration of cheetah (a) = 4m/s²
time = 10s
initial velocity(u) = 0
final velocity = v
distance travelled = s

v = u +at = 0 + 10×4 = 40m/s
s = (v²-u²)/2a = 40²/(2×4) = 1600/8 = 200m
   
6 0
3 years ago
For sprinters running at 12 m/s around a curved track of radius 26 m, how much greater (as a percentage) is the average total fo
Snezhnost [94]

Answer:

114.86%

Explanation:

In both cases, there is a vertical force equal to the sprinter's weight:

Fy = mg

When running in a circle, there is an additional centripetal force:

Fx = mv²/r

The net force is found with Pythagorean theorem:

F² = Fx² + Fy²

F² = (mv²/r)² + (mg)²

F² = m² ((v²/r)² + g²)

F = m √((v²/r)² + g²)

Compared to just the vertical force:

F / Fy

m √((v²/r)² + g²) / mg

√((v²/r)² + g²) / g

Given v = 12 m/s, r = 26 m, and g = 9.8 m/s²:

√((12²/26)² + 9.8²) / 9.8

1.1486

The force is about 114.86% greater (round as needed).

5 0
2 years ago
Can you guys help me
andreev551 [17]
B will be the answer
5 0
3 years ago
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