Potential energy because it has enough energy to do work but non has been done yet.
Either the first one or the second one but i believe it’s the stricter on
Assuming the raindrop was stationary relative to the vertical distance to the ground at the start:
D=0.5at where d is distance, a is acceleration and t is time
D is 300 meters
a is 9.8 meter/sec squared
Solve for t in seconds
t = 61.2 seconds
v=at where v is velocity
a is 9.8 meters per second squared
t is 61.2 seconds
solve for v
v = 600 meters per second.
If it had an initial vertical velocity (v0) at the start :
d= 0.5at+v0t
and
v=at+v0
The force applied would be 1.05*9.8 = 10.3 N
the pressure is equal to F/a
area will be πr^2 = 0.002826
thus pressure will be = 10.3/0.002826= 3644.72 N/m^2