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lesya [120]
3 years ago
14

Question:

Chemistry
1 answer:
IgorC [24]3 years ago
8 0

To learn and be used in life

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A flexible container at an initial volume of 6.13 L contains 6.51 mol of gas. More gas is then added to the container until it r
aivan3 [116]

Answer:

the final mole of the flexible container = 12.92 moles

Explanation:

Given that :

initial volume of a flexible container = 6.13 L

initial mole of a flexible container = 6.51 mol

final volume of a flexible container = 18.3 L

final mole of a flexible container = ???

Assuming the pressure and temperature of the gas remain constant, calculate the number of moles of gas added to the container.

Therefore,

n= \dfrac{V_2*n_1}{V_1}

n= \dfrac{18.3*6.51}{6.13}

n = 19.43

n=n_1+n_2

19.43 = 6.51 + n₂

n₂ = 19.43 - 6.51

n₂ = 12.92 moles

Thus; the final mole of the flexible container = 12.92 moles

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bamboo can grow 910 mm (36 in) within a 24-hour period,at a rate of almost 40 mm (1 1⁄2 in) an hour (a growth around 1 mm every 90 seconds, or 1 inch {2.54 centimeters} every 40 minutes).

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