The molar mass of this gas is 92.3 g/mol
Calculation
By use ideal gas equation PV =nRT where
n=mole p=pressure V= volume R = gas constant T= temperature
n = mass /molar mass(MM)
substitute in the equation
PV =(mass/MM)RT
mass = density x volume(V)
Therefore PV =(density xV/ MM) xRT
divide both side by by V
P= (density/Mm) xRT
making MM the subject of the formula
MM = densityPRT
At STP = P= 1 atm, R= 0.0821 L.atm/Mol.k T = 273 K
MM is therefore = 4.12 g/l x 1 atm x 0.081 L.atm/mol.k x 273 K = 92.3 g/mol
N2 + 3H2 ---> 2NH3
nitrogen + hydrogen ---> ammonia
You have to do a report :

So
the truck efficiency is 38%.
If it is incomplete or complete combustion. Normally the problems question with tell you.
EX:
"In the presence of plenty of oxygen" is complete combustion
"Not enough oxygen present" is incomplete combustion
The Answer to your question would be A